Display voltage from 8 channel mux in serial monitor

I’m trying to develop this code so the actual voltage is displayed in the serial monitor. Your assistance is appreciated.

int pin_Out_S0 = 8;
int pin_Out_S1 = 9;
int pin_Out_S2 = 10;
int pin_In_Mux1 = A0;
int Mux1_State[8] = {0};
//float Mux1_State[i] =0;
int RawValue=0;
float Voltage = 0;
void setup() {
  pinMode(pin_Out_S0, OUTPUT);
  pinMode(pin_Out_S1, OUTPUT);
  pinMode(pin_Out_S2, OUTPUT);
  pinMode(pin_In_Mux1, INPUT);
  Serial.begin(4800);
}

void loop() {
 RawValue = analogRead(pin_In_Mux1);
 Voltage = (RawValue * 5.0) / 1024; //scale the ADC
  updateMux1();
//Serial.println(Mux1_State);
  for(int i = 0; i < 8; i ++) {
    if(i == 7) {
  //Serial.print("Raw  Value = " );
//Serial.print(i);   
      
      Serial.println(Mux1_State[i]);
    } else {
      Serial.print(Mux1_State[i]);
      Serial.print(",");
//   vout = (value * 5.0) / 1024.0;
    
    }
  }
}


void updateMux1 () {
  for (int i = 0; i < 8; i++){
    digitalWrite(pin_Out_S0, HIGH && (i & B00000001));
    digitalWrite(pin_Out_S1, HIGH && (i & B00000010));
    digitalWrite(pin_Out_S2, HIGH && (i & B00000100));
    Mux1_State[i] = analogRead(pin_In_Mux1);
  }
}

What do you mean by "actual voltage" ?

The voltages from each pin of the 8 channel mux.