Do interrupt , interrupts serial.print()

I am using a quadrature rotary encoder (5000 pulses/rev ) and 600 rpm motor and using interrupts.
I googled it and found that serial.print takes approximately 86 uS (ie. 10s/115600).

I want to know that wether interupt is skipped while serial printing or not ?

here's my code :

#include <digitalWriteFast.h>  // library for high performance reads and writes by jrraines
                               // see http://www.arduino.cc/cgi-bin/yabb2/YaBB.pl?num=1267553811/0
                               // and http://code.google.com/p/digitalwritefast/

// It turns out that the regular digitalRead() calls are too slow and bring the arduino down when
// I use them in the interrupt routines while the motor runs at full speed creating more than
 
// Quadrature encoders
#define c_LeftEncoderInterrupt 3
#define c_LeftEncoderPinA 20
#define c_LeftEncoderPinB 21
#define LeftEncoderIsReversed
volatile bool _LeftEncoderBSet;
volatile long _LeftEncoderTicks = 0;
volatile boolean interrupt = 0;
void setup()
{
 Serial.begin(115200);

  // Quadrature encoders
  // Left encoder
  pinMode(c_LeftEncoderPinA, INPUT);  	// sets pin A as input
  digitalWrite(c_LeftEncoderPinA, LOW);  // turn on pullup resistors
  pinMode(c_LeftEncoderPinB, INPUT);  	// sets pin B as input
  digitalWrite(c_LeftEncoderPinB, LOW);  // turn on pullup resistors
  attachInterrupt(c_LeftEncoderInterrupt, HandleLeftMotorInterruptA, RISING);
 
}
void loop()
{

if(interrupt == 1)
 {
 Interrupt =0;
Serial.print(_LeftEncoderTicks);
 }

}
 
// Interrupt service routines for the left motor's quadrature encoder
void HandleLeftMotorInterruptA()
{
  // Test transition; since the interrupt will only fire on 'rising' we don't need to read pin A
  _LeftEncoderBSet = digitalReadFast(c_LeftEncoderPinB);   // read the input pin
 
Interrupt=1;

  // and adjust counter + if A leads B
  #ifdef LeftEncoderIsReversed
    _LeftEncoderTicks -= _LeftEncoderBSet ? -1 : +1;
  #else
    _LeftEncoderTicks += _LeftEncoderBSet ? -1 : +1;
  #endif
}

I want to know that wether interupt is skipped while serial printing or not ?

Which interrupt? The one involved in actually shifting the data out is not skipped. Your encoder interrupt is a higher priority interrupt, so it won't be skipped, either. It might be slightly delayed (while one character is handled by the serial interrupt), but not skipped.