I think a knowledgeable person can do the math:
(Vin - 5V) x current drawn = excess heat to be dissipated.
(12V - 5V) x 200mA for example = 1.4W of excess heat to dissipate with very little heatsinking to do it.
I think a knowledgeable person can do the math:
(Vin - 5V) x current drawn = excess heat to be dissipated.
(12V - 5V) x 200mA for example = 1.4W of excess heat to dissipate with very little heatsinking to do it.