Error in read EEprom in ESP8266

Using Arduino Programming Questions
#1

Hi, someone can help me, I’m trying to write and read long data in an eeprom memory of an ESP8266, but when reading the memory I always get zero, what is my error?

Here is my code:

#include <EEPROM.h>

int addr = 0;
long data = 65123;
byte high;
byte low;

void write_EEprom(long datax){
  EEPROM.write(0, highByte(datax));
  EEPROM.write(1, lowByte(datax));
  EEPROM.commit(); 
  }

void read_EEprom(long datax){
  high = EEPROM.read(0); 
  low = EEPROM.read(1); 
  datax = long((high << 8) + low);
  }

  
void setup(){
  Serial.begin(115200); 
  EEPROM.begin(512);  

  write_EEprom(data);

  data = 0;
  read_EEprom(data);
  
  Serial.print("El Dato1: ");   
  Serial.println(data);
  Serial.print("\n");  

  data++;
  write_EEprom(data);  

  data = 0;
  read_EEprom(data);
  
  Serial.print("El Dato2: ");   
  Serial.println(data);
  Serial.print("\n"); 
}
 
void loop(){
  delay(10);   
}
#2 
void read_EEprom(long datax){
  high = EEPROM.read(0);
  low = EEPROM.read(1);
  datax = long((high << 8) + low);
  }

That makes no sense and nothing is returned by the function.

long read_EEprom(){
  high = EEPROM.read(0);
  low = EEPROM.read(1);
  datax = long((high << 8) + low);
  return datax;
  }

Makes more sense. The function will then return a long data type.

read_EEprom(data);

Called that way the return value (if it had one) is discarded.

data = read_EEprom();

If the code for the read function is modified to return a value the above is a way to call the function.

#3

Or, you could pass the value to the function by reference:

void read_EEprom(long &datax)
{ // Down here, where the damned thing belongs
  high = EEPROM.read(0);
  low = EEPROM.read(1);
  datax = long((high << 8) + low);
}

Then, after this is called, the variable passed to the function IS modified.

#4