Error Message "expected primary-expression before ')' token"

Using Arduino Programming Questions
#1

So, I’m a beginner, and this code may seem a bit stupid, but i need help. The error message “expected primary-expression before ‘)’ token” keeps showing up, and I don’t know what it means. Someone help please. Thanks.

Code:
#include <LiquidCrystal.h>
LiquidCrystal lcd(11,9,6,5,4,3);

const int buttonPin = 2;
int buttonState = LOW;
int done = 0;

void setup() {
Serial.begin(9600);
pinMode(buttonPin, INPUT);

lcd.clear();
//lcd.print(“despacito”);
}

void loop() {
//int buttonState = LOW;

buttonState = digitalRead(buttonPin);

//lcd.print(buttonState);

if(digitalRead(buttonPin) == LOW && done == 0)); {
int buttonState = 1;
lcd.print(“despacito”);
done + 1;

}

if( digitalRead(buttonPin) == HIGH) {

lcd.clear();
done = 0;
}

}

#2

if(digitalRead(buttonPin) == LOW && done == 0)); Oops.

Please remember to use code tags when posting code.

#3

Oops.

Just in case it is not obvious, there are two problems with that statement. Your job is to find both of them.

#4

    done + 1;What ?

#5 
int buttonState = LOW;

    int buttonState = 1;

Two variables with the same name, but different scope, is a recipe for disaster.

#6