Error Status 1 (Error compiling for board Arduino/Genuino uno

Projects Programming
1

Hello,
I am pretty new on Arduino coding. I created the following code foe a 3 stores elevator
The idea is that once pushed the botton the motor will rotate in one or the other direction based on the position of the elevator to get to the floor.
I am getting the following error message:
[collect2.exe: error: ld returned 1 exit status

exit status 1
Error compiling for board Arduino/Genuino Uno.]

Any help/ suggestion would be appreciated

[
int potPin = 0;
int Button1 = 1;
int Button2 = 2;
int Button3 = 3;
int Switch1 = 4;
int Switch2 = 5;
int Switch3 = 6;
int Led1 = 7;
int Led2 = 8;
int Led3 = 9;
int L2 = 10;
int L1 = 11;
int St = 12;
int FLOOR;
int Busy;

void setup() {
pinMode(Button1, INPUT); // Button 1st floor
pinMode(Button2, INPUT); // Button 2nd floor
pinMode(Button3, INPUT); // Button 3rd floor
pinMode(Switch1, INPUT); // position swith Elevator 1st floor
pinMode(Switch2, INPUT); // position swith Elevator 2nd floor
pinMode(Switch3, INPUT); // position swith Elevator 3rd floor
pinMode(Led1, OUTPUT); // led 1st floor
pinMode(Led2, OUTPUT); // led 2nd floor
pinMode(Led3, OUTPUT); // led 3rd floor
pinMode(St, OUTPUT); // Power switches
pinMode(L1, OUTPUT); // Power motor exit 1
pinMode(L2, OUTPUT); // Power motor exit 2
Busy = 0; // internal variable define if the elevator is workind and unable push buttons
FLOOR = 0; // internal variable determine on which floor the elevator is going
}

void loop1() { //1ST FLOOR
if (Busy = 0);
if (Button1 == HIGH);
{
digitalWrite(St, HIGH);
}
if (Switch1 == LOW);
{ analogWrite(Led1, HIGH);
analogWrite(L1, HIGH);
analogWrite(L2, LOW);
Busy = 1;
FLOOR = 1;
}
}

void loop2() { //2ND FLOOR
if (Busy = 0);
if (Button2 == HIGH);
{
digitalWrite(St, HIGH);
}
if ((Switch2 == LOW) and (FLOOR == 1))
{ analogWrite(L1, LOW);
analogWrite(L2, HIGH);
analogWrite(Led2, HIGH);
Busy = 1;
FLOOR = 2;
}
else
{ analogWrite(L1, HIGH);
analogWrite(L2, LOW);
analogWrite(Led2, HIGH);
Busy = 1;
FLOOR = 2;
}
}

void loop3() { //3RD FLOOR
if (Busy = 0);
if (Button3 == HIGH);
{
digitalWrite(St, HIGH);
}
if (Switch3 == LOW);
{ analogWrite(Led3, HIGH);
analogWrite(L1, LOW);
analogWrite(L2, HIGH);
Busy = 1;
FLOOR = 3;
}
}

void loop4 () { //El_stop
if (Busy = 1);
if ((FLOOR == 1) and (Switch1 == HIGH))
{ (St == LOW);
analogWrite(St, LOW);
analogWrite(L1, LOW);
Busy = 0;
FLOOR = 0;
}
else if ((FLOOR == 2) and (Switch2 == HIGH))
{ (St == LOW);
analogWrite(St, LOW);
analogWrite(L1, LOW);
Busy = 0;
FLOOR = 0;
}
else if ((FLOOR == 3) and (Switch3 == HIGH))
{ (St == LOW);
analogWrite(St, LOW);
analogWrite(L1, LOW);
Busy = 0;
FLOOR = 0;
}
}
]

3 
 if (Busy = 0);
  if (Button2 == HIGH);

Not a compilation error-causer, but you really need to lose the semicolons.
Also "busy = 0" will always be false, so I don't think that's what you intended to do.

  { (St == LOW); I have no idea what that is supposed to do.

4 
int Button1 = 1;

 if (Button1 == HIGH);

Since HIGH is defined as 1, this statement will always be true. Of course, with the semicolon on the end, nothing will happen regardless of whether the statement is true or false.

int Switch1 = 4;
  if (Switch1 == LOW);

4 is not 0, so this statement will always be false. Not that it matters, with that ; on the end, since nothing happens either way.

Why do you have buttons and switches? How did you sew the buttons on? What do they actually do?

You have no loop() function. The loop1(), loop2(), loop3() and loop4() functions are never called.

That code is such a mess that you REALLY need to just delete ALL of it, and start over.

Learn about the really cool function called digitalRead() for starters.

5

Thank you all for the feed back.

6 
if (Busy = 0);
  if (Button1 == HIGH);

No, NO, NO

See above. (reply 2)

And please use code tags.

So I made my code work and I wanted to leave here for future reference.
It doesn't mean it's correct but at least i don't get any error message.

You should know that just because a sketch compiles without error doesn't mean that it is
a) Correct
or
b) Will work as you expect it to.