Exit status 1 redefinition of 'void setup()'

Projects Programming
1

Good Afternoon everyone, i'm working on a little project and i'm trying to make two codes run at the same time, i want the first one to read and display the data of that the sensor of the second code detects in a lcd display but i'm running into this error : exit status 1 redefinition of 'void setup()'

code:
'''

const int PINO_SENSOR = A0;

const int PINO_RELE = 2;

int leitura_sensor = 0;

bool pausa = true;

const int VALOR_MAXIMO = 900; //Valor com solo seco
const int VALOR_MINIMO = 700; //Valor com solo umido

const int CONCENTRACAO_MINIMA = 30;
const int CONCENTRACAO_MAXIMA = 50;

void setup()
{

pinMode(PINO_SENSOR, INPUT);

pinMode(PINO_RELE, OUTPUT);

digitalWrite(PINO_RELE, LOW);

}

void loop() {

leitura_sensor = analogRead(PINO_SENSOR);
leitura_sensor = map(leitura_sensor, VALOR_MINIMO, VALOR_MAXIMO, 100, 0);

if(leitura_sensor < CONCENTRACAO_MINIMA){ //Se sim
digitalWrite(PINO_RELE, HIGH); //Acionamos o rele
pausa = false;
} else if (leitura_sensor > CONCENTRACAO_MAXIMA) { //Caso contrario
digitalWrite(PINO_RELE, LOW);
pausa = true;
}

if(pausa){ //Se sim
delay(10000); //A linha acima aguarda 10 segundos para uma nova leitura
}

}

// include the library code:
#include <LiquidCrystal.h>

// initialize the library with the numbers of the interface pins
LiquidCrystal lcd(7,8,9,10,11,12);

int potPin1 = A1;
int potPin2 = A2;

// set up the LCD's number of columns and rows:
lcd.begin(16, 2);
lcd.clear();

pinMode(potPin1, INPUT);
pinMode(potPin2, INPUT);

lcd.setCursor(0,0); // Sets the cursor to col 0 and row 0
lcd.print("SensorVal1: "); // Prints Sensor Val: to LCD
lcd.print(analogRead(potPin1)); // Prints value on Potpin1 to LCD
lcd.setCursor(0,1); // Sets the cursor to col 1 and row 0
lcd.print("SensorVal2: "); // Prints Sensor Val: to LCD
lcd.print(analogRead(potPin2)); // Prints value on Potpin1 to LCD

'''

2

Hello
The sketch contains multiple functions calls for loop() and setup().

3

You can only have one setup() and one loop() function.

4

You need to merge the two pieces of code into a single setup() and a single loop() function. It is not enough to simply copy two programs together.

5

Thank you!

6

Thanks!

7

Thanks PaulPaulson and @ToddL1962

8

Hey guys @paulpaulson @ToddL1962 (and Kai-R) thanks for the help! i think i've managed to fix it doing what you guys said (i only used one loop and setup) but now i'm running into the following errors:

sketch_sep26a:61:1: error: 'lcd' does not name a type

lcd.begin(16, 2);

^~~

sketch_sep26a:62:1: error: 'lcd' does not name a type

lcd.clear();

^~~

sketch_sep26a:64:8: error: expected constructor, destructor, or type conversion before '(' token

pinMode(potPin1, INPUT);

    ^

sketch_sep26a:65:8: error: expected constructor, destructor, or type conversion before '(' token

pinMode(potPin2, INPUT);

    ^

sketch_sep26a:69:1: error: 'lcd' does not name a type

lcd.setCursor(0,0); // Sets the cursor to col 0 and row 0

^~~

sketch_sep26a:70:1: error: 'lcd' does not name a type

lcd.print("SensorVal1: "); // Prints Sensor Val: to LCD

^~~

sketch_sep26a:71:1: error: 'lcd' does not name a type

lcd.print(analogRead(potPin1)); // Prints value on Potpin1 to LCD

^~~

sketch_sep26a:72:1: error: 'lcd' does not name a type

lcd.setCursor(0,1); // Sets the cursor to col 1 and row 0

^~~

sketch_sep26a:73:1: error: 'lcd' does not name a type

lcd.print("SensorVal2: "); // Prints Sensor Val: to LCD

^~~

sketch_sep26a:74:1: error: 'lcd' does not name a type

lcd.print(analogRead(potPin2)); // Prints value on Potpin1 to LCD

^~~

exit status 1

'lcd' does not name a type

i appreciate any help, sorry for my mistakes i'm a beginner!

9

Post your updated code.
First, click the code tag button in the reply editor, it looks like this </>.
Then, paste your code where it says to.

10

posted!

11

Don't modify sketches in the existing posts. Post updated sketches in a new reply.

I think that you tried to use code tags but it did not quite work out. Instead of using ''', use ``` (called backticks)

12

You should take a look at the sample programs that are included with the IDE to memorize the structure of an Arduino C/C++ program.

I have adapted your code so that it can at least be compiled. But it is doubtful that the program works as you imagine it.

// include the library code:
#include <LiquidCrystal.h>

// initialize the library with the numbers of the interface pins
LiquidCrystal lcd(7, 8, 9, 10, 11, 12);

int potPin1 = A1;
int potPin2 = A2;

const int PINO_SENSOR = A0;
const int PINO_RELE = 2;

int leitura_sensor = 0;
bool pausa = true;

const int VALOR_MAXIMO = 900; //Valor com solo seco
const int VALOR_MINIMO = 700; //Valor com solo umido
const int CONCENTRACAO_MINIMA = 30;
const int CONCENTRACAO_MAXIMA = 50;

void setup() {
  pinMode(PINO_RELE, OUTPUT);
  pinMode(PINO_SENSOR, INPUT);
  pinMode(potPin1, INPUT);
  pinMode(potPin2, INPUT);

  digitalWrite(PINO_RELE, LOW);
  // set up the LCD's number of columns and rows:
  lcd.begin(16, 2);
  lcd.clear();
}

void loop() {

  leitura_sensor = analogRead(PINO_SENSOR);
  leitura_sensor = map(leitura_sensor, VALOR_MINIMO, VALOR_MAXIMO, 100, 0);

  if (leitura_sensor < CONCENTRACAO_MINIMA) { //Se sim
    digitalWrite(PINO_RELE, HIGH); //Acionamos o rele
    pausa = false;
  } else if (leitura_sensor > CONCENTRACAO_MAXIMA) { //Caso contrario
    digitalWrite(PINO_RELE, LOW);
    pausa = true;
  }

  lcd.setCursor(0, 0); // Sets the cursor to col 0 and row 0
  lcd.print("SensorVal1: "); // Prints Sensor Val: to LCD
  lcd.print(analogRead(potPin1)); // Prints value on Potpin1 to LCD
  lcd.setCursor(0, 1); // Sets the cursor to col 1 and row 0
  lcd.print("SensorVal2: "); // Prints Sensor Val: to LCD
  lcd.print(analogRead(potPin2)); // Prints value on Potpin1 to LCD

  if (pausa) { //Se sim
    delay(10000); //A linha acima aguarda 10 segundos para uma nova leitura
  }
}
13

Thanks man, i really appreciate it, it's for a school project, i'm a begginer in programming and in this forum but i'm trying my best! :slight_smile:

14

Ok, thanks!