Extracting Last number of array that is not a zero

Hi there i’m basically stuck trying to get the last number out of an array that is not a 0 so in this case 6. Can this be done? thanks for any help!!

int myArray[10]={3, 8, 5, 6, 9, 2, 5, 6, 0, 0};
int lastNumber;

void setup() {

 Serial.begin(115200);
 
 
}

void loop() {

 for (int i = 0; i < 9; i++)
  lastNumber = myArray[i];
 Serial.println(lastNumber);
 
}

Start from the end of the array, and work back.

TolpuddleSartre:
Start from the end of the array, and work back.

yeah i figured that but i have tried with no luck

int myArray[10]={3, 8, 5, 6, 9, 2, 5, 6, 0, 0};
int lastNumber;

void setup() {

 Serial.begin(115200);
 
 
}

void loop() {

 for (int i = 9; i < 9; i--)
 if(i > 0){
  
    lastNumber = i;
    
    
  }
  
 Serial.println(lastNumber);
 
}

Luck isn’t required.

int myArray[10]={3, 8, 5, 6, 9, 2, 5, 6, 0, 0};
int lastNumber;

void setup() 
{
 Serial.begin(115200);
}

void loop() {

 for (lastNumber = 9; lastNumber >= 0 && myArray [lastNumber] == 0; lastNumber--)
 {
 }
 Serial.println(myArray [lastNumber]);
 
}

I haven’t compiled or tested this.

TolpuddleSartre:
Luck isn't required.

int myArray[10]={3, 8, 5, 6, 9, 2, 5, 6, 0, 0};

int lastNumber;

void setup()
{
Serial.begin(115200);
}

void loop() {

for (lastNumber = 9; lastNumber >= 0 && myArray [lastNumber] == 0; lastNumber--)
{
}
Serial.println(myArray [lastNumber]);

}



I haven't compiled or tested this.

Wow it works!!! Thankyou very much!!!!

TolpuddleSartre:
Luck isn't required.

+1

LOL

...R