Hi there i'm basically stuck trying to get the last number out of an array that is not a 0 so in this case 6. Can this be done? thanks for any help!!
int myArray[10]={3, 8, 5, 6, 9, 2, 5, 6, 0, 0};
int lastNumber;
void setup() {
Serial.begin(115200);
}
void loop() {
for (int i = 0; i < 9; i++)
lastNumber = myArray[i];
Serial.println(lastNumber);
}
Start from the end of the array, and work back.
TolpuddleSartre:
Start from the end of the array, and work back.
yeah i figured that but i have tried with no luck
int myArray[10]={3, 8, 5, 6, 9, 2, 5, 6, 0, 0};
int lastNumber;
void setup() {
Serial.begin(115200);
}
void loop() {
for (int i = 9; i < 9; i--)
if(i > 0){
lastNumber = i;
}
Serial.println(lastNumber);
}
Luck isn't required.
int myArray[10]={3, 8, 5, 6, 9, 2, 5, 6, 0, 0};
int lastNumber;
void setup()
{
Serial.begin(115200);
}
void loop() {
for (lastNumber = 9; lastNumber >= 0 && myArray [lastNumber] == 0; lastNumber--)
{
}
Serial.println(myArray [lastNumber]);
}
I haven't compiled or tested this.
TolpuddleSartre:
Luck isn't required.
int myArray[10]={3, 8, 5, 6, 9, 2, 5, 6, 0, 0};
int lastNumber;
void setup()
{
Serial.begin(115200);
}
void loop() {
for (lastNumber = 9; lastNumber >= 0 && myArray [lastNumber] == 0; lastNumber--)
{
}
Serial.println(myArray [lastNumber]);
}
I haven't compiled or tested this.
Wow it works!!! Thankyou very much!!!!