Extracting numbers from an existing variable

Projects Programming
1

How do I get the first, second or third number directly, from an existing integer?For example, if x is considered to be 375635, is there any way to ask the board "Whats the first/second/third digit?" Thanks in advance.

2

What range of number values do you need to do this for ?

3

atoi (Ascii to integer) sticks the digits in an array and you can then access them one at a time:

char myChar[10];
int myInt = 12345;

void setup()
{
  Serial.begin(9600);
  Serial.println(itoa(myInt, myChar, 10));
  Serial.println(myChar[0]);
  Serial.println(myChar[1]);
  Serial.println(myChar[2]);
  Serial.println(myChar[3]);
  Serial.println(myChar[4]);
} //setup

void loop()
{

} //loop

12345
1
2
3
4
5
4

Is it a 6-digit decimal number : 000000 to 999999?

5

Or ltoa, Long to Ascii:

char myChar[10];
long myLong = 12435798;

void setup()
{
  Serial.begin(9600);
  Serial.println(myLong);
  ltoa(myLong, myChar, 10);
  Serial.println(myChar[0]);
  Serial.println(myChar[1]);
  Serial.println(myChar[2]);
  Serial.println(myChar[3]);
  Serial.println(myChar[4]);
  Serial.println(myChar[5]);
  Serial.println(myChar[6]);
  Serial.println(myChar[7]);
} //setup

void loop()
{

} //loop

12435798
1
2
4
3
5
7
9
8

The array needs to be long enough to hold the digits and the terminating null.

6

as an excercise you can do it yourself ,right ? divide by 10^n round to integer and store your digit...

7

Untested:

uint8_t getDigit(uint32_t num, uint8_t digit) {
  uint32_t tempNum;

  for (uint8_t i = 0; i < digit; i++) {
    num /= 10;
  }
  tempNum = num / 10;
  tempNum *= 10;
  return num - tempNum;
}
8

Thanks a lot!!!! I finally got my displays working.