Fading the LED without turning it off.

Using Arduino Programming Questions
1

Hi, guys. I'm completely noob in arduino for now.

I wonder, how can i turn on the LED, using fade-effect. WITHOUT turning it off.

I use

int PWMpin = 10; // LED in series with 470 ohm resistor on pin 10

void setup()
{
}

void loop()
{
   for (int i=0; i <= 255; i++){
      analogWrite(PWMpin, i);
      delay(10);
   } 
}

But, after fading in, the LED just turnes OFF and fade in again and again and forever. And other commands in my code(after for-commands) don't work. How to prevent it from turning off, until the 'analogWrite(PWMpin, 0)' command.

Thank you.

2

If " i " equals zero or if the required minimal voltage is not met, it will turn off.

3

HazardsMind:
If " i " equals zero or if the required minimal voltage is not met, it will turn off.

I mean how to prevent turning it off after it got 255? How to stop for-function from turning it of after each cycle and fade in it again and again.

I want to fade in the LED and let it be turned on, until I analogwrite 0 to it.

4

I have

digitalWrite(6, HIGH);
delay(100);
digitalWrite(5, HIGH);
delay(100);
digitalWrite(3, HIGH);
delay(20);

And I want to turn on the LEDs using fade - effect.

5

Black_Parrot:

HazardsMind:
If " i " equals zero or if the required minimal voltage is not met, it will turn off.

I mean how to prevent turning it off after it got 255? How to stop for-function from turning it of after each cycle and fade in it again and again.

I want to fade in the LED and let it be turned on, until I analogwrite 0 to it.

Look at the name of the function the for loop is in: loop. Guess what the loop function does after it is finished? That's right it loops and starts again. If you want better control over it, take a look at the blink without delay example. You can add logic to said example that emulates what a for loop does, but without indiscriminately setting the analogWrite value back to 0