get rid of one resistor

I have 2 IRleds, or they will bright up both at the same time or they both will be off.
Atm i have it like this:

5V-----LED-----R1-------GND
5V-----LED-----R2-------GND

But i wondered if i could do it like this:

5V-----LED-----LED-----R1-------GND

Atm i think this is correct,

R = V/I
for 1 led:
(5-1.3) / 0.075 = 50mA

for 2:
(5-2.6) / 0.075 = 32ma

is it?

Atm i think this is correct,

R = V/I
for 1 led:
(5-1.3) / 0.075 = 50mA

Correct math, however the answer, 50, is expressed in resistance units called ohms, so R= 50 ohms.

for 2:
(5-2.6) / 0.075 = 32ma

Again correct math, but answer is 32 ohms, not ma.

Lefty

i ment ohms.
thanks

Course, you're not gonna get 75mA out of an arduino pin if that's your goal here.

and you'll only be able to turn both of them on or both off, instead of them being separately controllable as in your first example.

Pete