A common default choice for a single power supply op amp is an LM324. But you don't want to use an op amp. Your PWM output is just switching on and off very rapidly, it isn't really an analog signal. There is a schematic in the playground for driving multiple LEDs from an Arduino pin, http://www.arduino.cc/playground/uploads/Learning/multiple_leds2.jpg, it is similar to what you want to do. Just replace all of those LEDs with a single gauge connected to your +10v supply instead of the Arduino +5v. You must also connect the ground of your 10v supply to the ground of your Arduino.
The transistor operates as a switch which is off at low voltage and on at high voltage, you could use a FET here too, but the circuit shows a bipolar. If you use a FET you could lose the resistor, but funny things might happen between powerup and you enabling the pin as an output unless you put a resistor to ground... so stick with the bipolar.
Now, assuming you don't have a 10V power supply already in your circuit, the easiest way to get one of those is to power your Arduino from a 10-12V power supply. The regulator in the Arduino will still take it down to 5V for the digital logic and it will be available at the "raw" power out pin for driving your gauges. You might find that the 9V unit you have now is already making over 10V... they get a little funny at low loads.
To keep from pegging your needles you will have to either limit the voltage in software by never going too high, or you could stick a resistor between the gauge and the transistor. The size of the transistor will depend on the current required to make your gauge go to full scale... I'll make up a number... 8ma... and calculate with that...
Let V+ = 12volts
let Ig = 8ma (current to peg gauge)
V+ = 10V + Ig*R + 0.2
... (10V is the voltage across the gauge when pegged, you called it a 10V gauge, 0.2 is the voltage across the bipolar transistor when full on.)
12v = 10v * 0.008a*R + 0.2
1.8v = 0.008a*R
R = 1.8v/0.008a
R = 225 ohms.
use a 220 ohm resistor, they aren't that accurate anyway.
If you still go over scale, then you guessed wrong at Ig, use a larger resistor until it works out.