Getting just one count++;

Projects Programming
1

So my problem is when i run

If (now.hour() ==00 && now.minute() == 00 && now.second() ==00)
{
Serial.print("hi");
}

I get anywhere from 3-8 hi's

Now. I need to filter that down to one "hi"

How would i go about it?
This has confused me for a bit

2

Record that you've already sent a 'hi' in this second. Next second, reset that to zero.

3

Only print when second becomes zero.

See the StateChangeDetection example in the IDE

4

The thing is second stays 0 for well a second.
Which is enough time for the arduino to fire off a few zeros.
So i get a few hi's.

I need only one

Like a delay but i dont even think millis() would help me right now...

Ive tried everything..

5

Also note, writing 00 is fine but do not the leading 0 indicates octal notation so 010 != 10 and 09 is NOT valid :wink: Aka, don't get into the habit of writing leading zero's if you don't mean octal :slight_smile:

6

The thing is second stays 0 for well a second.

Yes, but it only changes to 0 once a minute. Catch that change of state and print when it occurs.

7 
bool hiSent = false;

void loop()
{
   // Get the time
   if (now.hour() ==00 && now.minute() == 00 && now.second() ==00)
   {
      if(!hiSent)
      {
         Serial.print("hi");
         hiSent = true;
      }
   }
   else
   {
       hiSent = false;
   }
}

What the f**k this has to do with count++ is a complete mystery.

8

It has to do with count to count days. Duh!

And i just used now.day() instead

9

Isn't that as simple as

if(now.day() != lastDay){
  lastDay = now.day();
  days++;
}