GPIO/digitalWrite does not seem to work

Using Arduino Programming Questions
1

I am new to this forum but not to arduino and I am encountering a strange problem. Here is my code:

#define RECEIVER 3 //receiver to pin #
#define LEDPin 13

void setup() {
  pinMode(RELAIS, OUTPUT);
  digitalWrite(RELAIS, LOW);
  pinMode(LEDPin, OUTPUT);
  digitalWrite(LEDPin, LOW);
}

void loop() {
  digitalWrite(RELAIS, HIGH); digitalWrite(LEDPin, LOW);
  delay(1000);
  digitalWrite(RELAIS, LOW); digitalWrite(LEDPin, HIGH);
  delay(1000);
}

and I am uploading this code to an arduino pro mini 5V, 16MHz (using an arduino nano as ISP). Uploading is smooth:

Der Sketch verwendet 1372 Bytes (4%) des Programmspeicherplatzes. Das Maximum sind 30720 Bytes.
Globale Variablen verwenden 40 Bytes (1%) des dynamischen Speichers, 2008 Bytes für lokale Variablen verbleiben. Das Maximum sind 2048 Bytes.

When I run the code I do see the internal LED blinking and I am measuring 2.2V at pin 13. But at pin 2 (down to 12) I am measuring 0V the entire time. I do not understand this behavoir. Is there anybody who can point me to a solution? Thanks in advance, andies

2

The code you posted in incomplete.

This is NOT an installation and troubleshooting topic.

3

Pin 2 is not used in your program
RELAIS is not defined in your program

Have you posted the right one ?

4

Sorry I made a mistake when copying. And I possibly found the reason for the error. I used the following code:

#define RELAIS 11//relais to pin #D11

void setup() {
  pinMode(RELAIS, OUTPUT);
  digitalWrite(RELAIS, LOW);
}


void loop() {
        digitalWrite(RELAIS, HIGH);
        delay(300);
        digitalWrite(RELAIS, LOW);
        delay(700);//insgesamt eine Sekunde Pause
}

and tried all pins starting from D2 to D13. All Pins D2..D10 did not work. D11 till D13 do work. So it is not a programming error, instead the arduino (a Chinese clone) seems to be partially broken.

5

Or maybe the over-current or back EMF from the relay, damaged the pins.

6

No, I did not connect the relais yet (and if so then with a diode). Still: Thanks!