Hello,
I want to calculate how much current would flow if a short happens between battery terminals. I am using two 18650 batteries.
Battery specifications:
Product name: NCR1865034B Rechargeable Liion Battery
Voltage: 3.6v4.2v
Capacity:3400mAh
Output: 4.2v 600mA
Input: 110240v
Over charging:4.2v
Maximum charge: 1.5C
internal resistance: below 50 milliohm
Charging time: 1000 times
Weight: 48g
Size: 69.5mm x 18.5mm (length x diameter)
The PCB use 2*MOS protection board, maximum power voltage is 4.2V, the minimum voltage of 2.5V.
I have come up with two methods to calculate the current:

Using the formula, V=I * R, when the battery is fully charged (4.2 V) and internal resistance of 0.05 Ohms, then the current should be: 4.2/0.05 = 84 A?? Then, for 2 similar batteries, it would be 84x2 = 168A?? That just seems unrealistic to me.

But i'm also thinking that maybe another way to calculate the short current: since this battery is rated at 3400mAh, so if it's shorted, then for one battery, i should expect 3.4 A to flow??
I don't want to experiment to find out, in case my batteries get damaged or explode!