geoland:
Referring here. 3" of 22AWG Nichrome, requires approx 0.5 amps to increase its temperature by 20C (68F). The resistance through the wire is ~0.025R, and increase in R due to heating up to 20C very small - assuming zero.E = IR
E = 0.5 * 0.25 = 0.125v, is the voltage required to provide 0.5amps to a wire with a resistance of 0.025R and heat it 20C (68F) from 0C (32F). In which case given the very small R values in question, raising the temperature of the wire by 20C from any other temperature state, will require the same current and voltage.
Which is it? 0.025? or 0.25? ?
0.5A * 0.025? = 12.5mV (0.0125 V)