Help!!! Android app to HC-06

Using Arduino Installation & Troubleshooting
#1

So i Developed this app on MIT app inventor and i made a simple If Button 1 clicked call Bluetooth send text “1”

And i watched Electronoobs video about how to controll lamps and stuff, i need a 9 V pump and im using a transistor as a switch.

And i tried BTSerial from softwareserial, if it looks mesy… im kinda noob…

#include <SoftwareSerial.h>´
#include <Wire.h>
#include <RtcDS3231.h>
SoftwareSerial BTSerial(4,5);
RtcDS3231 Rtc(Wire);
int sensorPin = A0;
int sensorValue = 0;
int percent = 0;
int Pump = 4;
int Recieved = 0;
int Pump_state = 0;
void setup() {
Serial.begin(9600);
pinMode(Pump, OUTPUT);
Rtc.Begin();
Rtc.Enable32kHzPin(false);
Rtc.SetSquareWavePin(DS3231SquareWavePin_ModeNone);
BTSerial.begin(38400);
}
void loop() {
digitalWrite(Pump, LOW);
sensorValue = analogRead(sensorPin);
percent = convertToPercent(sensorValue);
printValuesToSerial();
delay(1000);
RtcTemperature temp = Rtc.GetTemperature();
if(BTSerial.read() > 0) {
Serial.print(BTSerial);
}
if(Serial.available() > 0){
Recieved = Serial.read();
}
if(Pump_state == 0 && Recieved == “1”) {
digitalWrite(Pump, HIGH);
Pump_state=1;
Recieved=0;
delay(10000);
}
if(percent > 50){
digitalWrite(Pump, HIGH);
delay(1);
if(percent > 50){
digitalWrite(Pump, LOW);
delay(2700000);
}
}
}

int convertToPercent(int value)
{
int percentValue = 0;
percentValue = map(value, 1023, 0, 0, 100);
return percentValue;
}

void printValuesToSerial()
{
RtcTemperature temp = Rtc.GetTemperature();
temp.Print(Serial);
Serial.print(“C”);
Serial.print("`");
Serial.print(percent);
Serial.print("%");
delay(5000);
}

PLANTA.ino (1.35 KB)

#2

Is there a question?
An inkling that this may not be the right section of the forum to post this?

#3

i need help with how i can make a if out of that signal on my arduino

#4

Try making more sense.

#5

ok i will try...

so i want so that when i click the button on my phone i want the pump to run... using the serial

#6 
  if(percent > 50){
    digitalWrite(Pump, HIGH);
    delay(1);
    if(percent > 50){
      digitalWrite(Pump, LOW);
      delay(2700000);
    }
  }

Explain what how you think the logic of that works.
Why does it have two "if"s, when one would work just as well.

#7

well that´s me being stupid

#8

Ok.
Come back when you’ve taken your stupid head off, and screwed on a sensible one.

#9

#include <SoftwareSerial.h>´
#include <Wire.h>
#include <RtcDS3231.h>
SoftwareSerial BTSerial(4,5);
RtcDS3231 Rtc(Wire);
int sensorPin = A0;
int sensorValue = 0;
int percent = 0;
int Pump = 4;
int Recieved = 0;
int Pump_state = 0;
void setup() {
Serial.begin(9600);
pinMode(Pump, OUTPUT);
Rtc.Begin();
Rtc.Enable32kHzPin(false);
Rtc.SetSquareWavePin(DS3231SquareWavePin_ModeNone);
BTSerial.begin(38400);
}
void loop() {
digitalWrite(Pump, LOW);
sensorValue = analogRead(sensorPin);
percent = convertToPercent(sensorValue);
printValuesToSerial();
delay(1000);
RtcTemperature temp = Rtc.GetTemperature();
if(BTSerial.read() > 0) {
Serial.print(BTSerial);
}
if(Serial.available() > 0){
Recieved = Serial.read();
}
if(Pump_state == 0 && Recieved == “1”) {
digitalWrite(Pump, HIGH);
Pump_state=1;
Recieved=0;
delay(10000);
}
if(percent > 50){
digitalWrite(Pump, HIGH);
delay(1);
digitalWrite(Pump, LOW);
delay(2700000);

}
}

int convertToPercent(int value)
{
int percentValue = 0;
percentValue = map(value, 1023, 0, 0, 100);
return percentValue;
}

void printValuesToSerial()
{
RtcTemperature temp = Rtc.GetTemperature();
temp.Print(Serial);
Serial.print(“C”);
Serial.print("`");
Serial.print(percent);
Serial.print("%");
delay(5000);
}

#10 
 if(percent > 50){
    digitalWrite(Pump, HIGH);
    delay(1);
    digitalWrite(Pump, LOW);
    delay(2700000);

Does the pump latch the one millisecond pulse?

Can you start using code tags when you post code, so we don't miss anything?

#11

the 1 delay is just me wanting to work with it at the moment, in the end it is suposed to be 20000

#12