HELP ME ,PLZ.

Projects Programming
1

if ( 11 == HIGH && 4 == HIGH && dly<= 500 )

{ digitalWrite(11,LOW); digitalWrite(8,HIGH); delay(100);}

else { digitalWrite(7, HIGH); delay(100); digitalWrite(7, LOW);}

HI, I have a big problem with that.

i have pin 11 as binary output.
pin 8 as digital output.
pin 7 as condition output.
pin 4 as digital input.

the issu is wen i push the button 4 the statement do not exute it self.

HELP ME ,PLZ,PLZ,PLZ.

2

if "11" & "4" are output pins, you can not use in this place. Those should be input or the boolean variable where you can store input/output/constant values.

if ( 11 == HIGH && 4 == HIGH && dly<= 500 )

Note: better assign name for each and every pin and use in code.

3

if ( 11 == HIGH

That's never going to happen, is it?

The IDE has many very basic examples of programming supplied.
I suggest you read through a few.

4

perhaps not

if ( 11 == HIGH . . .

but

if ( digitalRead( 11 ) == HIGH . . .

5

perhaps not

if ( 11 == HIGH . . .

but

if ( digitalRead( 11 ) == HIGH . . .

This also can not happen as the pin is defined as ouput pin and we try to read as digital input pin. This contradicts.

6

britto:
perhaps not

if ( 11 == HIGH . . .

but

if ( digitalRead( 11 ) == HIGH . . .

This also can not happen as the pin is defined as ouput pin and we try to read as digital input pin. This contradicts.

Does it?

7

Does it?

Its working. Sorry for the untested assumption before.

8

If the pin is an output then presumably the program sets it HIGH or LOW. Save this state in a variable when you do the digitalWrite() to the pin and use it later when you need to know the current state. No need for digitalRead() at all.

9

thnks, everybody.