Need an adjustable circuit.
*signal in 0-5v
*signal out 1v or 0v
*value to adjust is limit between 0-5v to go to 1v or 0v
Try something with a comparator and variable resistor to detect the input trigger voltage level and a voltage divider (two resistors) on the output side to achieve your 0 to 1 voltage range. If you need more current on the output side than the voltage divider can manage, then add an NPN transistor in emitter follower configuration.
Well, that would appear to deal with the otherwise inevitable question about the budget.
A comparator with a push pull output would seem more appropriate in that configuration.
The answers already posted will work but depending on how fast the signal changes, doing this in code might lead to a solution more quickly. Especially if an arduino is already being used in the project.
What are you hoping to do?
Assuming a push pull output comparator is used. An open collector type such as the LM393 will not work directly.
A simple divider bridge will cost you the price of 2 resistors.
Resistors are cheap, that is for sure, but you do not appear to have interpreted the OP's requirements in the same way as the other thread participants.
The output seems to be either 0 volts or 1 volts depending on the input voltage. That is, it is not linearly proportional to the input voltage.
by calculating the divider bridge with the maximum voltage (1v) its circuit should work.
The MAX9095 has an open-drain output, so it cannot source any current or voltage; it can only pull the line low. Therefore, it will not work unless a pull-up resistor is added. You can add a pull-up resistor to 1V and use the output directly without a voltage divider; this is one of the advantages of an open-drain (or open-collector) output.
Alternatively, you can use a simple voltage divider as suggested by @axelmaux, which can then be followed by a unity-gain buffer (voltage follower) for impedance isolation, such as this:
