High power LED efficiency

I am interested in running some high power 3 Watt LEDs, and I want to use them as efficiently as possible. This is difficult because all the companies I've looked at so far (Bridgelux, Cree, Phillips etc) rate their efficiency in lumens per watt (lm/w), which is heavily biased towards the green spectrum. I am only concerned with the amount of photons produced e.g umol-s / watt.

Not really expecting company specific answers, im more interested in general LED efficiency. As I understand the higher current you drive them at the greater magnetic field is created at the band gap which results in losses as heat. Though I am dubious to believe that it is simply a matter of driving them at the lowest possible foward voltage... Can anyone shed some light on this?

Here is a link to the datasheet for an example LED in consideration: http://www.philipslumileds.com/uploads/265/DS68-pdf

True.

If a high power led gets half the current, the light is still more than half. So the efficiency has increased.

The graphs for flux against current in the datasheet look very good. It is almost linear.
Cheap power leds are much less linear, and have massive loss at normal currents.

Looking at the graphs of these good quality power leds, I think half the normal current increased the efficiency a little.
With very good cooling, you can use half the normal current. But if you can't cool the led enough, you might have to lower the current more. The 'amber' led produces only half the flux at 70 degrees Celsius.

A visual trick is to blink a led. When blinking with about 200Hz or more, the human eye can't keep up and sees the led with a brighter light. With 50% signal, the current is 50%, but the human eye might see it as 60%. So the visual 'efficiency' increases.

ADDED: See reply 11. No change in visual light intensity.

Erdin:
A visual trick is to blink a led. When blinking with about 200Hz or more, the human eye can't keep up and sees the led with a brighter light. With 50% signal, the current is 50%, but the human eye might see it as 60%. So the visual 'efficiency' increases.

Are you claiming a 200Hz PWM light looks brighter than the equivalent steady photon flux?

Yes.
The PWM of analogWrite() uses a frequency near 500Hz. That can be used for this.

ADDED: See reply 11. No change in visual light intensity.

You may find this interesting —

http://www.lightbased.com/files/White_Papers/LinearvsPWMSummary_-_FINAL.pdf

MarkT:
Are you claiming a 200Hz PWM light looks brighter than the equivalent steady photon flux?

Erdin:
Yes.
The PWM of analogWrite() uses a frequency near 500Hz. That can be used for this.

Have you actually tried this? You will find that it does not work.

Think about it. How does PWM dim an LED? By turning it on and off. If your assertions were true then dimming would not work.

I have met some professional engineers that believe this as well but it is not true. As they found out when they tried it.

The efficiency of LEDs are best at low temperatures, but if you use energy to cool down the LED, that should be considered as an inefficiency. For photosynthesis, red light is useful and also, it has less energy than green photons. Energy is h*f where h is planck's constant and f is light frequency. Since red light has a lower frequency than green, each photon has less energy. This does not directly mean that red LEDs are more efficiant than green, since different semiconductors are used.

You want to maximize the mols of photons, you said. One mol is an Avagadros Number of photons. The following link discusses that:
http://www.autogrow.com/general-info/light-measurement

Conclusion
There is no simple answer to best efficiency for LEDs. There are answers that are complicated because of:

1 material science trade secrets on LEDs
2 low temperatures in a greenhouse are bad for photosynthesis and good for LEDs.
3 cooling an LED with Peltier effect bimetal strips uses more energy than is gained by efficiency
3 magnetic fields in LEDs are not important, I expect. (Hall effect)

As I understand the higher current you drive them at the greater magnetic field is created at the band gap which results in losses as heat.

no.
AmbiLobe has it right:-

magnetic fields in LEDs are not important,

http://www.nicadd.niu.edu/research/e...ab-tm-2308.pdf
It says:-

CONCLUSIONS
Measurements performed using various LEDs in the
magnetic field point to the insensitivity of the LED’s light
output on the field strength of up to 2.3T within 1%.

Visual Efficiency

Thanks for the answers guys, some good discussion going on here. However as I said I am not really interested in visual efficiency, hence why I am not interested in luminous efficiency. For example if altering the frequency as mentioned increases the "visual efficiency" due to increased photon flux (more photons per area), then yes it applies.

I am aware of electrons, energy levels, and the energy cost vs penetration power/frequency of different wavelengths e.g. Planck's law etc.. But this does not really matter, it is only for a given wavelength that I am interested.

If your talking about photosynthesis then yes, red light is more photsynthetically efficient than blue, despite having a lower energy and penetration. Then its a matter of electrical efficiency, i.e the amount of power required to change the energy level of electrons for the appropriate wavelength of light to be emitted.

1ChicagoDave:
You may find this interesting —

http://www.lightbased.com/files/White_Papers/LinearvsPWMSummary_-_FINAL.pdf

Thanks, it does look interesting. I haven't read it yet but I don't think you can get more light by blinking the LED, it probably only appears brighter to us.

Electrical/Photon Flux efficiency

Erdin:
True.

If a high power led gets half the current, the light is still more than half. So the efficiency has increased.

The graphs for flux against current in the datasheet look very good. It is almost linear.
Cheap power leds are much less linear, and have massive loss at normal currents.

Looking at the graphs of these good quality power leds, I think half the normal current increased the efficiency a little.
With very good cooling, you can use half the normal current. But if you can't cool the led enough, you might have to lower the current more. The 'amber' led produces only half the flux at 70 degrees Celsius.

Yes as you can see they are quite linear, which also makes me wonder if the gained efficiency is worth it. Then it becomes a light per area (photon flux) problem. Yes it might increase the efficiency of light produced for one LED, but how many LED's over what area? Will feeding twice the number of LED, at half the amount of current, over the same distribution area, yield an equal or greater photon flux? (probably assuming no distribution due to lens angles and the inverse square law)

Cooling

Will two LEDs at half the current produce less heat than one LED at full current? I'm working on a passive water-cooled design. Basically slice a heatsink parallel to the fins to get a bunch of single-finned heatsinks, spread apart for more surface area cooling, make a groove on the underside to house a copper pipe, which loops from the bottom of the heatsink to above the heatsink between the fins. The idea being that the hot air rising off the fins will pull cool air from below and cool the copper pipe between the fins above, then the copper is filled with some high thermal capacity liquid (like water) and thus circulates passively. There should be enough temperature difference at the top of the copper pipe and the bottom housed in the heatsink to create enough flow, but what about the thermal capacity of the water? Is this idea only viable with a large external resevoir? Also fans don't use much electricity while drastically increasing air flow, so I might opt for some kind of hybrid design, but this means I have to have an enclosure to direct the air flow and I was basically hoping to have the heat sinks exposed.

LED droop/Auger effect

As for the magnetic field causing LED droop, I was referring to this, a nice article on how the Auger effect possibly relates to droop:

Grumpy_Mike:
No. AmbiLobe has it right:-

http://www.nicadd.niu.edu/research/e...ab-tm-2308.pdf
It says:-

CONCLUSIONS
Measurements performed using various LEDs in the
magnetic field point to the insensitivity of the LED’s light
output on the field strength of up to 2.3T within 1%.

Thanks but I can't get the link to work. How recent is this document? I think what I am describing was only recently discovered.

The Auger effect is not a magnetic effect. The linked article is not about magnets. The Auger effect is a loss in LED's efficiency because an electron and hole recombine without emitting a photon: they emit another electron that may not contribute to light.

Conclusion : magnetism is not important. The efficiency of LEDs is a research area with a level of detail not suitable to typing on a chat room. If money is no object then , yes, buy 10 times as many LEDs, drive them with 1/10 the current so they are cool.

Grumpy_Mike:
Think about it. How does PWM dim an LED? By turning it on and off. If your assertions were true then dimming would not work.

I have met some professional engineers that believe this as well but it is not true. As they found out when they tried it.

That's the point. A 50% PWM does increase the visual light to human eye compared to a DC current of half that.
I tried this in the past and it was true. Perhaps I will try it tomorrow.

This is a fork of the original question, but still interesting.

ADDED: See reply 11. No change in visual light intensity.

I did the test with the light intensity to the human eye.

Two new equal white leds. Two 10 stroke potentionmeters to tune the current.
Pin 2 HIGH, set to current of 0.5mA for the led with the DC current.
Pin 11 a PWM of 50% of 1mA (pulses of 1mA).
I used sunglasses to compare them better.
I also tried lowering the PWM frequency, and 25% PWM of 2mA and 12.5% PWM of 4mA.
The change I noticed was a slight change of the color (more yellow, less blue for the PWM), but not the light intensity.

Result: It looks equally bright, I could not tell the difference.

1ma pulses (50% on/off) is the same as 0.5ma direct (limited) current.

I found it interesting you said there was a color change, a blueish tint tends to mean it's getting hot when over driven, and yellow is under driven... a better question is how much heat dissipation is there, I mean look at some data sheets, 2amps dc, or 6amps pulsed.... is it a linear correlation ?

cjdelphi:
I found it interesting you said there was a color change, a blueish tint tends to mean it's getting hot when over driven, and yellow is under driven...

Isn't it the other way round? Band gap voltage decreases with increasing temperature. For an extreme example on the effect on an LED, see Overclocking Arduino with liquid nitrogen cooling. 20⇒65.3Mhz @-196°C/-320°F : Svarichevsky Mikhail about half way down.

The white LED with 50% duty cycle has an unknown material and unknown manufacturer, so speculation about its physics is premature. Here is a link about efficiency and white color LEDs.

The encyclopedia of laser physics:

AmbiLobe:
The white LED with 50% duty cycle has an unknown material and unknown manufacturer, so speculation about its physics is premature. Here is a link about efficiency and white color LEDs.

My fault - somehow I failed to notice that the test was being done with white LEDs.

Are white LEDs more or less electrically efficient than say blue? I read somewhere that they were more efficient for the actual amount of light they put out but then I read in another paper the opposite. Are the RGB whites or the phosphor coated better? Also White LEDs usually output quite a bit in the green spectrum, and in the link http://www.rp-photonics.com/light_emitting_diodes.html it again contradicts what I had read elsewhere that the green spectrum is mor efficient to reproduce, this link says opposite.

Does anyone have any information on actual light output vs drive current? What would be the efficiency gain of using twice as many LEDs at half the current? This is hard to justify as it effectively doubles the cost, it better improve the efficiency by at least 25%

Also could my passive cooling idea work? Or is the water cooling part just unpractical?

Okay....it's killing me that nobody has asked or answered the following yet —

For what purpose are all these highly efficient, water-cooled photon generators going to be used?
:astonished:

"Are white LEDs more or less electrically efficient than say blue?"

A simple question for a complicated industry. It is natural for people to want simple answers, but face the facts: eight thousands facts, of which, seven thousand facts are trade secrets of billion dollar engineering efforts worldwide today. The answer is available after deep study of the IEEE Transactions on Electron Devices and the conference proceedings of the ISSCC International Solid State Circuits Conference. I will research the answer for you if you meet my wage demands.

"I read somewhere that they were more efficient for the actual amount of light they put out but then I read in another paper the opposite. "

You read press releases from marketing departments of two vast corporations.

"Are the RGB whites or the phosphor coated better? "

I like phosphors better because the spectrum is broader the the narrow band illusion of whiteness. Better at selling units to an uneducated cheap public? That information is a trade secret.

"Also White LEDs usually output quite a bit in the green spectrum, and in the link http://www.rp-photonics.com/light_emitting_diodes.html it again contradicts what I had read elsewhere that the green spectrum is more efficient to reproduce, this link says opposite."

The link from the RP corporation was approved by their marketing department. Marketing people are known to be biased in favor of products they are selling.

"Does anyone have any information on actual light output vs drive current?"

Yes.

"What would be the efficiency gain of using twice as many LEDs at half the current?"

The temperature will be lower, so the figures for the product you linked allow you to estimate the gain yourself. Or you can pay a highly educated expert to read your literature for you.

"This is hard to justify as it effectively doubles the cost, it better improve the efficiency by at least 25%"

That 25% is only a guess.

"Also could my passive cooling idea work?"

Yes.

"Or is the water cooling part just unpractical?"

It is practical for the unknown purpose.

AmbiLobe:
"Are white LEDs more or less electrically efficient than say blue?"

A simple question for a complicated industry. It is natural for people to want simple answers, but face the facts: eight thousands facts, of which, seven thousand facts are trade secrets of billion dollar engineering efforts worldwide today. The answer is available after deep study of the IEEE Transactions on Electron Devices and the conference proceedings of the ISSCC International Solid State Circuits Conference. I will research the answer for you if you meet my wage demands.

Wow ok a little bit patronizing there. I am aware that I'm asking a very general question, of which very specific variables are at play. This doesn't mean with some basic research we can't find at least a general solution. For example ("Blue LED's are more efficient than red and green, therefore the phosphor-coated blue LEDs are generally more efficient than the RGB combination") Not saying that information is accurate, just an example - without citations.

If you have any valuable information that I can't find myself through internet research then I would consider a collaberation of some kind, if you are interested. If not, stop patronizing me. I also know someone on the board for IEEE.

AmbiLobe:
"I read somewhere that they were more efficient for the actual amount of light they put out but then I read in another paper the opposite. "

You read press releases from marketing departments of two vast corporations.

Who said anything about marketing? This was university based research, nothing to do with marketing or corporations (except for the department, which I don't think is selling anything). Though I do understand your point, I am careful of the research I take into account.

AmbiLobe:
"Are the RGB whites or the phosphor coated better? "

I like phosphors better because the spectrum is broader the the narrow band illusion of whiteness. Better at selling units to an uneducated cheap public? That information is a trade secret.

I am really only interested in performance at this point. Trade secrets? I've come across a few, and selling cheap units to an uneducated cheap public isn't really a secret.

AmbiLobe:
The link from the RP corporation was approved by their marketing department. Marketing people are known to be biased in favor of products they are selling.

I know this as well. Which is why I try aim for scientific information rather than pseudo-marketing science. Yes this information is from the RP corporation and may be biased. However the information they present seems well researched and documented, and therefore is viable for analysis. Or are there secret links between universities and companies? Now thats information worth paying for.

AmbiLobe:
"Does anyone have any information on actual light output vs drive current?"

Yes.

Alright, do you have any specific information of photon efficency across a range of well known companies for a variety of spectrum? Have you compared luminous efficiency of various brands?

AmbiLobe:
"What would be the efficiency gain of using twice as many LEDs at half the current?"

The temperature will be lower, so the figures for the product you linked allow you to estimate the gain yourself. Or you can pay a highly educated expert to read your literature for you.

Well just looking at the table I see the "Deep red" at 350mA has a luminous efficacy of 46%, while the 700mA has 42%. So only 6% more efficient at half the current. The Relative Luminous Flux only varies by about 2.5% for temperatures between 20 and 40 degrees celcius for the "Deep red". The blue LEDs seem to vary even less with temperature. From an initial perspective its not enough to justify the 2x increase in distribution area due to twice as many LED's. I guess thats why some companies overdrive their LED's at the minimal expense of increased heat.

AmbiLobe:
"This is hard to justify as it effectively doubles the cost, it better improve the efficiency by at least 25%"

That 25% is only a guess.

"Also could my passive cooling idea work?"

Yes.

"Or is the water cooling part just unpractical?"

It is practical for the unknown purpose.

I worked out for myself that the efficiency gain isn't really substantial enough. There are undoubtedly more factors to consider than I took into account - hence the aim of the discussion.

The unknown purpose is probably out of the scope of this thread, and once practical applications start becoming a factor even more variables will need to be considered. For now I am interested in how to consolidate information from various brands, reading the datasheets is difficult because of the way they are ordered. I'm still learning how the codes work etc..