How can I determine the Tj value?

I am calculating heatsink for TIP3055 transistor. I want to obtain 4 ampere current from the collector.

Firstly I found the Tj value without heatsink from the formula Tj-Ta=QjaxPd.

According to the datasheet Qja = 35.7 and I determined Ta = 50.

From the datasheet VCE(sat) = 1.1 Vdc and the ampere I want is 4.

Then
Pd=VCE(sat)xIc
Pd=1.1x4=4.4W

Subsequently
Tj-50=35.7x4.4
Tj=207.08

Tj value is above the maximum value of 150 °C in the datasheet.
According to this situation, I assume that I should use a heatsink.

How can I determine the Tj value for the following heatsink formula?

Tj-Ta=Pdx(Qjc+Qcs+Qsa)

Should I use the Tj value which I calculated without heatsink?

Also, Qcs value is not given in the datasheet. Is there a standard value for Qcs?

I would be glad if you can help.

Hth;

TJ=P(Rcase+R1+R2)+Ta

You might consider replacing the TIP3055 with a MosFet. I would be easy to find a MosFet that can pass 4 amps while dissipating < 0.3 watts.

Look at Digikey or Mouser. They both have MosFet parameter filters.

If you still want to go the TIP3055 route be sure you understand the heatsink parameters. All heatsink's are spec'd in "free air". If you are in a case the heatsink will not perform the same as free air.

Why the 70-year old 2N3055.
Those ancient parts need 0.5 to 1Amp base current to switch 4Amp.
They are almost useless in today's electronics.
Leo..

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Even though equation somewhat is Fine (three thermal resistances are to consider), neither description nor formular implementation are consistent or correct.

Consider the attached example, for which a negative power is calculated :face_with_monocle:. And even the value itself is wrong
Values are samples following the figure (of the website showing heatsink and semiconductor) despite the fact that the figure is not calling for R1 or R2


Power should be 110/11.1 Watts

This datasheet?

image

That would seem sensible

You need the Thermal resistance of the heatsink to ambient, the thermal resistance of the thermal paste layer, and ambient temperature.

Just found this one

Even though about resistors, applicablr principles are the same and examples given.
From the data sheet, only Rth,JC is required provided you actually do use a heat sink

If you assume an ambient of 30C, let's say you find a max temp of 60C acceptable for the heatsink. At 4W this means a heatsink of at most 7.5K/W. Be conservative and pick something a little bigger, e.g. 5K/W. Try it out and if things still get too hot, improve airflow in your housing.

Or do the sensible thing, save materials, space and money and get a small MOSFET to do the switching virtually without any loss. No heatsink required, only a small PCB footprint.

In addition, they were never designed for switching (i.e. low Vcesat) but for analog usage (i.e. amplifiers)

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