How can I solve this code error in Servo.cpp?

Hi there,
I am new to this kind of programming and I have a compiler warning on the Servo library:
C:\Program Files (x86)\Arduino\libraries\Servo\src\avr\Servo.cpp:184:39:

warning: unused parameter 'timer' [-Wunused-parameter]

static void finISR(timer16_Sequence_t timer)

I found the piece of code here:
static void finISR(timer16_Sequence_t timer)
{
//disable use of the given timer
#if defined WIRING // Wiring
if(timer == _timer1) {
#if defined(AVR_ATmega1281)||defined(AVR_ATmega2561)
TIMSK1 &= ~_BV(OCIE1A) ; // disable timer 1 output compare interrupt
#else
TIMSK &= ~_BV(OCIE1A) ; // disable timer 1 output compare interrupt
#endif
timerDetach(TIMER1OUTCOMPAREA_INT);
}
else if(timer == _timer3) {
#if defined(AVR_ATmega1281)||defined(AVR_ATmega2561)
TIMSK3 &= ~_BV(OCIE3A); // disable the timer3 output compare A interrupt
#else
ETIMSK &= ~_BV(OCIE3A); // disable the timer3 output compare A interrupt
#endif
timerDetach(TIMER3OUTCOMPAREA_INT);
}
#else
//For arduino - in future: call here to a currently undefined function to reset the timer
#endif
}

The error is in the first line: static void finISR(timer16_Sequence_t TIMER)

So my question is:
How can I repair this piece of code? I.e. The TIMER is obvious wrong, but what do I replace with?

Thanks,
Jos

The error is in the first line

What error? A warning is NOT an error.

Yes, I agree that a warning is not an error.... But it annoyes me..... It should not be there and it pops up every time I compile my sketch. So I want to get rid of it...

If it REALLY bothers you, add

   timer = 57;

after

#else

When compiled for the Arduino, the compiler sees (after the post processor gets done):

static void finISR(timer16_Sequence_t timer)
{
    //disable use of the given timer
//For arduino - in future: call here to a currently undefined function to reset the timer
}

And, of course, the argument timer is NOT used.

#else
    timer = timer; //For arduino - in future: call here to a currently undefined function to reset the timer
#endif

This removes the warning without generating code.

Whandall:

#else

timer = timer; //For arduino - in future: call here to a currently undefined function to reset the timer
#endif



This removes the warning without generating code.

I get why, after a minute. Perhaps you'd like to explain to OP why what works.

Thanks!

This did the trick:

timer = timer; //For arduino - in future: call here to a currently undefined function to reset the timer

The sketch compiled fine.

Cheers,
Jos

The "check for unused parameter"-instance of the compiler only looks for uses
and the optimizer will remove the statement which has no effect.