how do I store the no1 in permeant memory

Okay, thought I had this licked but.......

having issues with SMS1 not storing now and thought I had all three working earlier.

updated to void Current() // when run it prints out the 3 stored values.

void Current()
{
  /*Serial.println("Current Mobile No:");
}
eeprom_read_string(0, buf, BUFSIZE);
Serial.println(buf);
Serial.println("Current Mobile No 2:");
eeprom_read_string(11, buf, BUFSIZE);
Serial.println(buf);*/
//
int i;
  for (i = 0; i < 3; i++) {
  Serial.print("Current Mobile No:");
  Serial.println(i+1);
eeprom_read_string((i*11), buf, BUFSIZE);
Serial.println(buf);
}
}

created a TestLoop() rather than edit the existing number()

code below:- // this should allow the three numbers to be inputed into EEPROM, however currently only appears to be work for 2 and 3, confirmation and possible solutions appreciated, or what to look at.

void TestLoop()
{
  int i;
  for (i = 0; i < 3; i++) {
    Serial.print("Input Mobile Number: ");
    Serial.println(i+1);
  
    while(Serial.available()==0){}//wait for user input
    no1 = Serial.readString(); //read input
    Serial.println(i+1);
    Serial.println(no1);
    if(no1.startsWith("SMS"+((i+1)),0)){  
      delay(20);
    Serial.print("Saving variable string to address: ");
    Serial.println(i*11);
    delay(20);
    no1s = no1.substring(4);
    myString=no1s;
    delay(20);
    myString.toCharArray(myStringChar, BUFSIZE); //convert string to char array
    strcpy(buf, myStringChar);
    delay(20);
    eeprom_write_string((i*11), buf); 
    delay(20);
    Serial.print("Reading string from address : ");
    Serial.println(i*11);
    eeprom_read_string((i*11), buf, BUFSIZE);
    Serial.println(buf);
    delay(20);
  
    }
    
    
    
  }

}