How do I turn on/off a buzzer using a IRremote and analogWrite?

Hi, I need to turn on/off a buzzer (no matter what sound makes) with a IRsensor and a IRcontrol.
But the question is, I don't how to do it using only with analog values. Here's my code:

#include <IRremote.h>
#define boton1 0x61F440BF
#define boton2 0x61F4C837
#define boton3 0x61F430CF
#define boton4 0x61F46897
#define boton5 0x61F428D7
#define boton6 0x61F4E817
#define boton7 0x61F418E7
#define azul 0x61F4B04F
#define mute 0x61F450AF
#define apagado 0x61F458A7
int SENSOR=11;
IRrecv irrecv(SENSOR);
decode_results codigo;

void setup() {
  pinMode(2,OUTPUT);
  pinMode(3,OUTPUT);
  pinMode(4,OUTPUT);
  pinMode(5,OUTPUT);
  pinMode(6,OUTPUT);
  pinMode(7,OUTPUT);
  pinMode(8,OUTPUT);
  pinMode(9,OUTPUT);
  pinMode(10,OUTPUT);
  Serial.begin(9600);
  irrecv.enableIRIn();
}

void loop() {
if(irrecv.decode(&codigo)) {
  Serial.println(codigo.value, HEX);
  switch(codigo.value){
    case boton1:
      if (digitalRead(2))
      digitalWrite(2,LOW);
      else
      digitalWrite(2,HIGH);
    break;
    case boton2:
          if (digitalRead(3))
      digitalWrite(3,LOW);
      else
      digitalWrite(3,HIGH);
    break;
    case boton3:
      if (digitalRead(4))
      digitalWrite(4,LOW);
      else
      digitalWrite(4,HIGH);
    break;
    case boton4:
      if (digitalRead(5))
      digitalWrite(5,LOW);
      else
      digitalWrite(5,HIGH);
    break;
    case boton5:
      if (digitalRead(6))
      digitalWrite(6,LOW);
      else
      digitalWrite(6,HIGH);
    break;
    case boton6:
      if (digitalRead(7))
      digitalWrite(7,LOW);
      else
      digitalWrite(7,HIGH);
    break;
    case boton7:
      if (digitalRead(8))
      digitalWrite(8,LOW);
      else
      digitalWrite(8,HIGH);
    break;
    case azul:
      if (digitalRead(10))
      digitalWrite(10,LOW);
      else
      digitalWrite(10,HIGH);
    break;
    case mute: //[This is the problem, I need to turn on/off the buzzer using only analogic values. No 
     tone() nor noTone()
      if (analogRead(9,75));
      else
      analogWrite(9,0);
    break;
    case apagado:
      if (apagado){
      digitalWrite(2,LOW);
      digitalWrite(3,LOW);
      digitalWrite(4,LOW);
      digitalWrite(5,LOW);
      digitalWrite(6,LOW);
      digitalWrite(7,LOW);
      digitalWrite(8,LOW);
      digitalWrite(10,LOW);
      analogWrite(9,0);}
   break;
  }
  irrecv.resume();
  }
  delay(100);
}

The problem:

case mute: //[This is the problem, I need to turn on/off the buzzer using only analogic values. No 
     tone() nor noTone()
      if (analogRead(9,75));
      else
      analogWrite(9,0);
    break;

Thanks for your attention.

 if (analogRead(9,75));

Please explain what this line of code is supposed to do ?

At the very least an if statement is very unlikely to end with a semicolon.

UKHeliBob:

 if (analogRead(9,75));

Please explain what this line of code is supposed to do ?

At the very least an if statement is very unlikely to end with a semicolon.

Yeah, I noticed that. I just need to turn on/off the buzzer by pressing one single button.

I know the whole mute case is wrong. I just don't know how to do it. I've searching for answer but I dind't find anything useful.

case mute: 
    buzzer = !buzzer;
    if (buzzer)
        analogWrite(9,75);
    else
        analogWrite(9,0);
    break;

Thanks! I'll try it.