How to choose a protection diode (power)

so I can easilly compute dissipation by multiplication 0.5 * 1*10^-6, is this correct?

Yes that is right.

Diode is not linear.

A diode's linearity is the way voltage varies with current. It is because the diode is not linear (in the way it is) that you can use it with a constant voltage drop no matter what current you put through it.