How to convert char* to char ?

Projects Programming
1

Hello all,

please how to convert char* to char ?

the last line of this code is error because the " var " is type of char but the " result " is char* ,
How can I take a number from the result to var so I can be use var as number like ' if ( var > 2 ) { }'

//***********************************
char result[ 10 ] , temp[ 10 ];
char var;

void setup(){
memset( result, 0, sizeof( result));
}

void loop(){

var = 123 ;
itoa( var, temp, 10);
strncpy( result, &temp[1],1);

var = result ;
//************************************

2

To convert a char pointer to a char is meaningless and pointless.

Please, please remember to use code tags when posting code.

3 
  memset( result, 0, sizeof( result));

Write over all of the NULLS that the compiler put in result with more NULLS. Why?

   strncpy( result, &temp[1],1);

As opposed to:

result[0] = temp[1];

? Why?

Or

var = temp[1];

? Why?

4

PaulS:

  memset( result, 0, sizeof( result));

Write over all of the NULLS that the compiler put in result with more NULLS. Why?

   strncpy( result, &temp[1],1);

As opposed to:

result[0] = temp[1];

? Why?

Or

var = temp[1];

? Why?

in my Example the result will be take one digit of the number, but if I write this code:-

 var = temp[1];

the var not take one digit because var not char*

5

the var not take one digit because var not char*

The value in temp[1] is not a pointer, either.