How to pass a function pointer to a function?

Projects Programming
1

Good day!

I have already created a topic about function pointer and with colleagues figured out how from the description. Even wrote a structure for the console command interpreter.

However, I can not describe the function, which has one argument - a pointer to a function. Syntax C/C++ is normally allows.

void
setup ()
{
  subfunc ("sssssssssssss", &strprint);
}

void
loop ()
{
}

int
subfunc (char *str, int (*func)(char *))
{

  func (str);

  return (0);
}

int
strprint (char *str)
{
  
  Serial.print ("[");
  Serial.print (str);
  Serial.println ("]");
  
  return (0);
}

When compiling my 0022 wrote:

sketch_apr23b.cpp: In function 'void setup()':
sketch_apr23b:7: error: 'subfunc' was not declared in this scope

I believe that I am describing the function, so that 0022 does not recognize subfunc() as function.

What am I doing wrong?

Ogogon.

2

Declare subfunc before its first use...

3

MarkT:
Declare subfunc before its first use...

Simple as that!
And indeed, it worked out!

Thank you very much.

Ogogon.