How to run infinite loop while counter is on specific number

[dpustahija]

Hi,
I have a project with Arduino, an oled screen, and a button.
I have 3 voids with text/images/gigs that work on screen.

want to create a program that shows:
while counter is on 1: void1 in infinite loop
while counter is on 2: void2 in infinite loop
while counter is on 3: void3 in infine loop
counter is incrementing on button push
I know how to setup 99% of code but I don't know how to exit an infinite loop (how to increment state of button while in infinite loop and exit it)

[anon73444976]

@dpustahija

but I don't know how to exit an infinite loop (

break, usually.

(They're called "functions" not "voids")

[alto777]

Let’s have a look at your functions.

What are gigs in this context?

a7

[dpustahija]

void xxx1() {
  display.clearDisplay(); //for Clearing the display
  display.setTextSize(4);
  display.setTextColor(WHITE);
  display.setCursor(20,20);
  display.print("xxx1");
  display.display();
  delay(3000);
}
void xxx2() {
  display.clearDisplay(); //for Clearing the display
  display.setTextSize(4);
  display.setTextColor(WHITE);
  display.setCursor(20,20);
  display.print("xxx2");
  display.display();
  delay(3000);
}

void slika() {
//this code shows gif on oled screen
}

void state1(){
  xxx1();
  slika();
  xxx2();
  slika();
  }

void loop() {
  int a=digitalRead(3);
  if(a==1){
    count=1+count;
    Serial.println(count);
    delay(500);}

//this is pseudocode of what i whant:
    *do: state1 in infinite loop*
*        while:  state is **1***

}

[anon73444976]

Unfortunately, a break isn't going to get you out of a delay.

[paulpaulson]

Hello dpustahija
Code a array of function pointers.
Have a nice day and enjoy coding in C++.

[alto777]

Read here. It seems like the trick in #4 would be within your abilities.

How to End a Loop instantly

thanks for your reply , i am new in arduino , can you help me to put "return" in correct place in the source code , here is my code ... //From ESP8266 we will run 10 LED int digiPin = 11; int digiPin2 = 12; int ledPin = 2; int ledPin2 = 3; int ledPin3 = 4; int ledPin4 = 5; int ledPin5 = 6; int ledPin6 = 7; int ledPin7 = 8; int ledPin8 = 9; int ledPin9 = 10; // select the pin for the LED int pinVal = 0; int pinVal2 = 0; void setup() { Serial.begin(9600); …

HTH

a7

[dpustahija]

I don't see how this answers my question of changing var value when the button is pressed inside of an infinite loop and exiting loop

[Paul_KD7HB]

You have not shown us your infinite loop, yet.

[alto777]

@dpustahija

I don't see how this answers my question

Sry.

How to End a Loop instantly

One quick and dirty option is to write a 'myDelay()' function that checks the button while waiting for time to expire. If the button is pressed, have it return 'true'. If the time expires, have it reurn 'false'. Then, in your code, replace "delay(100);" with if (myDelay(100)) return; The 'return;' statement will exit from loop() which will then be called again and will detect that the button is pressed. bool myDelay(unsigned long delayTime) { unsigned long startTime = millis(); whi…

Number 7. I always get 4 and 7 confused.

a4

[dpustahija]

I need a solution for the infinite loop. i don't have it.

this is a list of 15 images converted to 15 Bitmap HEX Codes. this has to be in loop to show gif from images and have small delays between them.

void slika() {
//this code shows gif on oled screen
}

i have 3 functions(3 gifs) that i what when i press button once hows gif1, press again shows gif2 ...

[alto777]

@dpustahija

void slika() {
//this code shows gif on oled screen
}

Post that code. The solution I pointed you at correctly last time I hope, would be a quick and dirty solution in this case I have no doubt.

a7

[johnwasser]

Your loop() function is already inside an infinite loop so maybe this sort of thing is what you are looking for:

void loop()
{
  if (digitalRead(3) == HIGH)
  {
    count += 1;
    Serial.println(count);
  }

  switch (count)
  {
  case 1: state1(); break;
  case 2: state2(); break;
  case 3: state3(); break;

  default: count = 0; break;
  }
}

Note: "count += 1;" is a shortcut for "count = count + 1;"

Note: The switch/case statement is a shortcut for:

  if (count == 1)
    state1();
  else if (count == 2)
   state2();
  else if (count == 3)
    state3();
  else 
    count = 0;

[paulpaulson]

Hello dpustahija
See below a example sketch based on functions pointer. You may tailor this sketch to your needs.

/* BLOCK COMMENT
  ATTENTION: This Sketch contains elements of C++.
  https://www.learncpp.com/cpp-tutorial/
  Many thanks to LarryD
  https://europe1.discourse-cdn.com/arduino/original/4X/7/e/0/7e0ee1e51f1df32e30893550c85f0dd33244fb0e.jpeg
  https://forum.arduino.cc/t/how-to-run-infinite-loop-while-counter-is-on-specific-number/958680
*/
#define ProjectName "How to run infinite loop while counter is on specific number"
// HARDWARE AND TIMER SETTINGS
// YOU MAY NEED TO CHANGE THESE CONSTANTS TO YOUR HARDWARE AND NEEDS
constexpr byte ButtonPins[] {A0};      // portPin o---|button|---GND
// VARIABLE DECLARATION AND DEFINITION
unsigned long currentTime;
struct TIMER {              // has the following members
  unsigned long duration;   // memory for interval time
  unsigned long stamp;      // memory for actual time
};
struct BUTTON {             // has the following members
  byte pin;                 // port pin
  bool statusQuo;           // current state
  TIMER scan;               // see timer struct
};
BUTTON selector {ButtonPins[One], false, 20, 0};
// User Tasks 
void (*tasks[])() {
  task0, task1, task2, task3
};
void task0() {
  Serial.println(__func__);
}
void task1() {
  Serial.println(__func__);
}
void task2() {
  Serial.println(__func__);
}
void task3() {
  Serial.println(__func__);
}
// -------------------------------------------------------------------
void setup() {
  Serial.begin(9600);
  Serial.println(F("."));
  Serial.print(F("File   : ")), Serial.println(__FILE__);
  Serial.print(F("Date   : ")), Serial.println(__DATE__);
  Serial.print(F("Project: ")), Serial.println(ProjectName);
  pinMode (LED_BUILTIN, OUTPUT);  // used as heartbeat indicator
  //  https://www.learncpp.com/cpp-tutorial/for-each-loops/
  for (auto Input : ButtonPins) pinMode(Input, INPUT_PULLUP);
}
void loop () {
  currentTime = millis();
  digitalWrite(LED_BUILTIN, (currentTime / 500) % 2);
  static int number = 0;
  tasks[number]();
  if (currentTime - selector.scan.stamp > selector.scan.duration) { // debounce button
    selector.scan.stamp = currentTime;
    int stateNew = ! digitalRead(selector.pin);
    if (selector.statusQuo != stateNew) {
      selector.statusQuo = stateNew;
      if (stateNew)
        ++number %= sizeof(tasks) / sizeof(tasks[0]);
    }
  }
}

Have a nice day and enjoy coding in C++.

[david_2018]

You can do this in more than one way, depending on what you actually want to do.

One way is to check if the value of the counter has changed, and if it has then execute the appropriate function. That will run the function once when counter changes, and then the program sits in loop checking the button to see if it has been pressed.

Another way is to check the value of counter in loop, then call the appropriate function depending on the value of counter. Afterwards, the function returns and you continue with loop, checking the button and then executing the same function again until the button is pressed, incrementing counter and going to the next function. This will execute the function repeatedly as long as counter remains the same.

[alto777]

@david_2018

That will run the function once

His function, the main one, is expressed as an infinite loop. So running it once will mean running it forever. There will be no "afterwards".

And this

void task3() {
  while (1) {
     Serial.println(__func__);
     delay(400);
  }
}

Is more like what is being looked at, abstract-wise.

@johnwasser clever quick dirty trick hack is the OP's best hope.

a7

[dpustahija]

Thanks this worked with minimal tweaking