How to solve this error while EEPROM write?

Projects Programming
1

I have code to write data into EEPROM,
when i write name_changecharater buffer into EEPROM its work.but when i write iBaseX and iBaseY its give error message ,how to solve this issue ?please help.
Thanks.

#include <EEPROM.h>

char name_change[32];
double iBaseX = 20000;
double iBaseY = 20000;
void writeEEPROM(int startAdr, int laenge, char* writeString) {
EEPROM.begin(512);
yield();
Serial.println();
Serial.print("writing EEPROM: ");
//write to eeprom
for (int i = 0; i < laenge; i++)
{
EEPROM.write(startAdr + i, writeString*);*
_ Serial.print(writeString*);_
_ }_
_ EEPROM.commit();_
_ EEPROM.end();_
_}_
_void readEEPROM(int startAdr, int maxLength, char dest) {
* EEPROM.begin(512);*
* delay(10);*
* for (int i = 0; i < maxLength; i++)*
* {*
dest = char(EEPROM.read(startAdr + i));
* }
 EEPROM.end();
 Serial.print("ready reading EEPROM:");
 Serial.println(dest);
}
void setup() {
 Serial.begin(9600);
 delay(100);_
strcat(name_change, "SMART TIMER");
writeEEPROM(0, 32, name_change); //32 byte max length*
* writeEEPROM(1, 32, iBaseX);*
* writeEEPROM(2, 32, iBaseY);*
* Serial.println("everything saved...");*
* readEEPROM(0, 32, name_change);
_ readEEPROM(1, 32, iBaseX);
 readEEPROM(2, 32, iBaseY);
}
void loop() {
 Serial.println("Loop");
 delay(1000);
}*_

2

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Look at the signature of your writeEEPROM function:

void writeEEPROM(int startAdr, int laenge, char* writeString) {

What makes you think you can pass a double to that function?

Just use EEPROM.put() and EEPROM.get():

3

How can i store double variable in EEPROM?

4

As I said, use EEPROM.put(). Did you bother to read the documentation at the links I provided?

Remember that on the ESP8266 you need to call EEPROM.commit() or EEPROM.end() before the data written to "EEPROM" actually gets stored in non-volatile memory:
https://arduino-esp8266.readthedocs.io/en/2.6.2/libraries.html#eeprom
Your writeEEPROM function does this, but I feel obligated to mention it anyway since you don't seem to have any understanding of what that function actually does.