If's & else if's without void loop

[alexokaban]

@joeltenzing

Okay I see.thanks for the answer My idea was that the robot would do a certain maneuver when only the left sensor detects an object. When only the right sensor detects an object it would do a different maneuver. And when both detect an object it would do an even different maneuver. I'd want it to execute the maneuver after the sensors detected the object(s). And then come back to the first place where an other object would be, etc. It would do it 3 times.

Hi. Have you programmed using a state machine?. I advice you to look into this way of approach. It uses a switch statement which handles the possible states of the machine. In your case when the robot senses an obstacle the code must set a state corresponding to the event. Lets say:

left sensor sets up left_sensor_state
right sensor sets up right_sensor_state
both sensors sets up both_sensor_state

then your loop() has a function called check_state();

and check_state() has your:

switch (state)

case left_sensor_state
do this
break;

like that with other 2 or 3 cases, or as many as you want.

I've coded using several state machines at the same time and its pretty stable. It feels like pseudomultitasking,.

Remember to always have a none_state kind of state, where your code "waits" for action like nothing occurs during the none_state. Here an example for the definition:

typedef enum
{
  STATE_NONE,
  STATE_LEFT,
  STATE_RIGHT,
  STATE_BOTH,
  STATE_START,  
} states;

states current_state = STATE_START; // current state-machine state

And also remember always after performing the action / maneuver to return the state to STATE_NONE, usually right before the break.

Regards