Im getting a non defined variable error, but every other place compiles fine?

Projects Programming
1

So, in my code, im making a little game about reaction timing, and I have an error about a non declared variable on the fourth if statement, but on the three previous if statements it compiled fine, I will put the loop and the function with the error

void flashLight() {
  //4 if statements running at same time to check what number the random produced
  if (randomLight == 1) {
    digitalWrite(light1, HIGH);
    bu1 = 1;
  }
  if (randomLight == 2) {
    digitalWrite(light2, HIGH);
    bu2 = 1;
  }
  if (randomLight == 3) {
    digitalWrite(light3, HIGH);
    bu3 = 1;
  }
  if (randomLight == 4) {
    digitalWrite(light4, HIGH);
    bu4 = 1;
  }
}

Function ^^^
Loop ///

void loop() {
  int randomLight = random(1, 4);
  flashLight();
  beginCountdown();
  // put your main code here, to run repeatedly:

}

Error /

exit status 1
'randomLight' was not declared in this scope

I dont know why tho, bye for now!

2

int randomLight
make this a global variable.

3

You declared a local variable named 'randomLight' in loop().

The variable named 'randomLight' in flashLight() is not declared.

Sounds like you want to declare 'randomLight' as a GLOBAL varible, outside any function, so it can be used to communicate between the two functions that use it.

4

oh my god, thanks, didnt realize that, heh heh, thanks!

5

I was also told that you only put the variable ontop of the if statement when you are using

6

SkyCrafter:
I was also told that you only put the variable ontop of the if statement when you are using

Could you repeat that in English?

Steve

7

You should read the documentation on the random() function. random(1,4) will sort-of-randomly return 1, 2, or 3. There is no sense in testing that the value is 4.

8

PaulS:
You should read the documentation on the random() function. random(1,4) will sort-of-randomly return 1, 2, or 3. There is no sense in testing that the value is 4.

Thanks, I never quite read it to the fullest

SkyCrafter:
I was also told that you only put the variable ontop of the if statement when you are using

Could you repeat that in English?

Steve
ENGLISH: I was also told that you only put the variable ontop of the if statement when you are using

9

SkyCrafter:
Steve
ENGLISH: I was also told that you only put the variable ontop of the if statement when you are using

Thanks, that clears it up nicely apart from just a couple of little things...what does "ontop of the if statement" mean? Oh and "when you are using" what? Heroin? A big hammer? Something else?

The individual words are mainly English, but the sentence is meaningless.

Steve

10

yeah it is, I didnt quite finish it,
Ontop = Line above
When you are using if statement