In the arduino pro mini, the Vcc is input or output ?

Hi guys,

I have the arduino pro mini, I'm supplying it through the raw pin with 9v volts.
I want to power my sensor with 5v (the arduino is 5v).

I don't understand if I can use the Vcc pin ?
Some people say it's input if I want to bypass the voltage regulator, others say it is an output.

What is it ?

It's both correct and you can use it as a 5V source (you can't draw much current from it, though)

lg, couka

VCC is a power rail.
You can say it's both input and output.

The onboard 5volt regulator supplies power to that rail (you could also do that with an external 5volt supply).
And you draw power from it (to power your sensors).

How sensitive is the arduino to voltage.
4 Batteries of 1.5 volts will be too much ?

Will bypassing the voltage regulator pull less current ?

If this is a 5 volt pro mini.
4 x 1.5 = 6v therefore if you use a series silicon diode .7 you can get down to 4.3v
edit, 5.3v
This would work.
Add a schottky diode .2v then you will get to ~5.1v, even better.

However, 3 batteries and a boost converter would be my recommendation.

4 x 1,5V = 6V is to much for Vcc (and to little for the RAW). 5,5V absolute maximum. But a bit lower is fine. 4,5V, no problem even with a 16MHz crystal. From the top of my mind (but you can look it up in the datasheet of the ATmega328p) its stable at 16MHz up until a little under 4V.

Max voltage is 5.5v per datasheet.

Could probably drop 0.7v through a normal (non-schottky) diode to get 4 AA’s into safe territory. I would not add a schottky diode after that; 5.3 is safe, and that’ll give you more headroom as the batteries run down.

Bypassing the regulator (by supplying 5v directly) will not reduce the current (though since you don’t need to give it an extra 2v for the dropout, the power (ie, volts times amps) is lower)

Removing the regulator from the board entirely will slightly reduce power consumption, but the quiescent current of the regulator isn’t that high - it’s only relevant when the chip is sleeping and you’ve already removed the power LED.

Spec for 16mhz is ya, a little under 4v. In practice, under normal conditions, you can generally run a 16mhz '328p down to 3.6v no problem (which is relevant as that’s the min output voltage for a LiPo battery)

If the AAs are rechargeable (NiMH) then you can probably power directly without using anything to drop the voltage. Even when fully charged, I don't think 4 of them would exceed 5.5V when any appreciable current was drawn.

Note that 1.5V is a nominal value, fresh alkaline cells deliver 1.6-1.65V. 4 x 1.65V = 6.6V which is too much, even with a Si-Diode in series.

As larryd suggested, 3 cells + boost converter are safer and more consistent.

lg, couka