INA219 current and voltage not display in LCD

Using Arduino Displays
1

Hi, may anyone helps me? How can I display current and voltage in arduino uno and display it through LCD? May anyone check my program incase there's problem or error.

#include <Wire.h>
#include <Servo.h>
#include <LiquidCrystal_I2C.h>
#include<LcdBarGraphRobojax.h>
#include <INA219_WE.h>
#define I2C_ADDRESS 0x40

INA219_WE ina219 = INA219_WE(I2C_ADDRESS);
Servo myservo;
LiquidCrystal_I2C lcd(0x27, 16, 2);

float voltage1;

void setup()
{
lcd.begin();
lcd.backlight();
lcd.clear();
Serial.begin(9600);
lcd.begin();
lcd.backlight();
lcd.clear();
lcd.setCursor(0,0);
lcd.print("SOLAR and PIEZO");
lcd.setCursor(4,1);
lcd.print("SYSTEM");
delay(10000);
lcd.clear();

Serial.begin(9600);
Wire.begin();
if(!ina219.init()){
//lcd.clear();
Serial.println("INA219notconnected!");
lcd.print("INA219 conneted");
}
Serial.println("INA219 Current Sensor with solar panel");
}

void loop() {

float shuntVoltage_mV=0.0;
float loadVoltage_V=0.0;
float busVoltage_V=0.0;
float current_mA=0.0;
float power_mW=0.0;
bool ina219_overflow=false;
float a;
float power;

shuntVoltage_mV = ina219.getShuntVoltage_mV();
busVoltage_V = ina219.getBusVoltage_V();
current_mA = ina219.getCurrent_mA();
a=abs(current_mA);
power_mW = ina219.getBusPower();
loadVoltage_V = busVoltage_V + (shuntVoltage_mV/1000);
ina219_overflow = ina219.getOverflow();

Serial.print("Shunt Voltage [mV]: "); Serial.println(shuntVoltage_mV);
Serial.print("Bus Voltage [V]: "); Serial.println(busVoltage_V);
Serial.print("Load Voltage [V]: "); Serial.println(loadVoltage_V);
Serial.print("Current[mA]: "); Serial.println(a);
Serial.print("Bus Power [mW]: "); Serial.println(power_mW);

lcd.clear();
lcd.setCursor (8,0);
lcd.print("|");
lcd.setCursor (8,1);
lcd.print("|");
lcd.setCursor (0,0);
lcd.print("VS:");
lcd.setCursor(0,1);
lcd.print("IS:");
//VS and IS display but no values

lcd.setCursor(3,0);
lcd.print((float)loadVoltage_V,1);
lcd.setCursor(7,0);
lcd.print("V");
lcd.setCursor(3,1);
lcd.print((float)a);
lcd.setCursor(6,1);
lcd.print("mA");

if(!ina219_overflow){
Serial.println("Values OK - no overflow");

float volt1 = analogRead(A1);
voltage1 = (volt1* 5.0/1024);

Serial.print("voltage1= "); Serial.println(voltage1,2);

lcd.setCursor (9,0); //
lcd.print("P:");
lcd.setCursor (11,0); //
lcd.print(voltage1); // print
lcd.setCursor (15 ,0); //
lcd.print("V");

lcd.setCursor (9,1); //
lcd.print("P:");
lcd.setCursor (11,1); //
lcd.print(voltage1); // print
lcd.setCursor (14 ,1); //
lcd.print("mA");

power= (loadVoltage_V*(a/1000))+(voltage1);
delay (2000);
//lcd.clear();

lcd.setCursor(0,0);
lcd.print("Power:");
lcd.setCursor (7,0); //
lcd.print(power); // print
lcd.setCursor (11 ,0); //
lcd.print("W");
delay (5000);
}
else{
Serial.println("Overflow! Choose higher PGAIN");
}
Serial.println();

delay(5000);
}

2

One issue with the posted code, its missing code tags.

When you ran the I2C scanner did it report success with finding the attached I2C devices?

would you want Wire.begin() before trying to do an I2C thing like start up the LCD?

How many lcd.begin()'s do you need? 2, 3, 4 or just 1?

3

the I2C device display the VS and IS but without the values of the current and voltage.
I'm new with arduino and circuit, could you explain more details about "lcd.begin();"?

4

Thanks for that bit of info.

Edit your original post, please, and enclose your code in code tags.

5

after you embed code rightly, show picture where is shown how you connected INA219 module.

6

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