Per the data sheet of the RFID reader and the IC used in this reader (http://www.emmicroelectronic.com/webfiles/product/rfid/ds/EM4095_DS.pdf), by increasing the Q factor of the inductor, I can increase the p-p voltage of the inductor and the peak current.
Also, the Q factor can be increased by reducing the inductors resistance. What would happen in an RLC circuit if I ran a resistor in parallel to the inductor?