incrementing an unsigned long

I have a program that produces a square wave at a chosen frequency and a chosen duty cycle . They are both unsiged longs

unsigned long Freq = 6; // the chosen frequency in Hz
unsigned long Duty = 30; // the chosen duty cycle in %

What I would like to do is increment the frequency between 1hz and 6hz say 10pulses at 1hz........ 10pulses an 6 hzs and then back to 1 .
I've been looking into how to increment unsigned longs but not really got anywere.

since is 1…6 and 10 pulses, WHY are you using ‘unsigned long’. a uint8_t would be more that enough!

regarding your request now, is this something like this you after:

uint8_t freq_Hz[6] = {1,2,3,4,5,6};
uint8_t pulses = 10;
uint8_t duty = 30;

unsigned long period_ms;
unsigned long OnTime;

for(uint8_t i=0; i<6;++i){ //cycle through the 6 elements of freq_Hz array
	period_ms = 1000/freq_Hz[i]; //calculate the period in ms of freq_Hz[i]
	OnTime = (period_ms*100)/duty; //calculate from % duty cycle the ON time in ms;
	
	for(uint8_t j=0; j<pulses;++j){
		digitalWrite(out_pin, HIGH); //you define what your output pin is
		delay(OnTime);
		digitalWrite(out_pin, LOW);
		delay(period_ms - OnTime);
	}
}

depending on you requirements, you could implement using ‘millis()’ if you need an non-blocking code…

hope that helps.

thanks I'll give it a go :slight_smile:

I've been looking into how to increment unsigned longs but not really got anywere.

Although you don't need to use unsigned longs I would be fascinated to see what you tried

This program works excatly how I want . just had to alter one thing

OnTime = (period_ms*duty)/100;
The duty and 100 were around the wrong way.
Thanks again

I've been looking into how to increment unsigned longs but not really got anywere.

Using a construct like "x++" did not work for you?