Initiailizing different pins from code

Hey, I need to initialize different pins from some code I got from someone else, but i am not too code savvy, so i was wondering if instead of initializing pins 0-7, I could initialize pins 0,1,2,4,5,6,7,8 instead? Thank you!!

/*
 Copyright 2007 Richard Cappels used with his permission
 www.projects.cappels.org
 This assumes an R/2R DAC (or other DAC) connected to PORTD, and
 Arduino 16mhz clock
 The frequency measured at the output of the DAC is 1.007 kHz.
 ported to arduino by hotcarrier
 output to pd7-pd2 with 6 bits- needs high order pd7 to work
 correctly
 */

#include <avr/interrupt.h>
#include <stdlib.h>
char sinetable [32];
int  i ;

void ioinit (void)
{
  //Initialize output ports
  PORTD = B11111111;
  DDRD  = B11111111;

}

void timer_setup(){
  TCCR2A = 0;
  TCNT2= 520;    //455 outputs 1.007khz
  TCCR2B = B00000010;
  //Timer2 Overflow Interrupt Enable
  TIMSK2 = 1<<TOIE2;
}
void setup(){           
  ioinit();
  arraysetup();
  cli();
  timer_setup();
  i = 0;
  sei();

}


ISR(TIMER2_OVF_vect) {
  PORTD=(sinetable[i++]);
  TCNT2=548;
  if(i==32){
    i=0;
  }

}
void arraysetup(void){
  sinetable[0]=127;  // Put 32 step 8 bit sine table into array.
  sinetable[1]=152;
  sinetable[2]=176;
  sinetable[3]=198;
  sinetable[4]=217;
  sinetable[5]=233;
  sinetable[6]=245;
  sinetable[7]=252;
  sinetable[8]=254;
  sinetable[9]=252;
  sinetable[10]=245;
  sinetable[11]=233;
  sinetable[12]=217;
  sinetable[13]=198;
  sinetable[14]=176;
  sinetable[15]=152;
  sinetable[16]=128;
  sinetable[17]=103;
  sinetable[18]=79;
  sinetable[19]=57;
  sinetable[20]=38;
  sinetable[21]=22;
  sinetable[22]=10;
  sinetable[23]=3;
  sinetable[24]=0;
  sinetable[25]=3;
  sinetable[26]=10;
  sinetable[27]=22;
  sinetable[28]=38;
  sinetable[29]=57;
  sinetable[30]=79;
  sinetable[31]=103;
}
void loop()
{
  
  while (1)
  {

  }

}

Pin 8 is PORTB,0, so :

PORTD = B11110111;
DDRD  = B11110111;

And:

PORTB = B00000001;
DDRB = B00000001;

But you are aware that pins 1 and Pin 8 is PORTB,0, so :
PORTD = B11110111;
DDRD = B11110111;

PORTB = B00000001;
DDRB = B00000001;

But you are aware that pins 0 and 1 are the serial RX and TX pins? are the serial RX and TX pins?

I actually was aware, and i did not think it would work, but it still seems to be working fine. I honeslty have no clue why, I am using the code in conjunction with a DAC to create a sin wave, and it does not seem to interfere with the output. Btw, is there any way that instead of declaring the pins in the way, I could just declare them independently? I find that is just easier to keep track of for me

outsider:
Pin 8 is PORTB,0, so :

PORTD = B11110111;

DDRD  = B11110111;



And:


PORTB = B00000001;
DDRB = B00000001;



But you *are* aware that pins 1 and 2 are the serial RX and TX pins?

I wasn't aware of that.
I thought it was pin zero and pin one.

digitalWrite(8,HIGH);
PinMode(8,OUTPUT);

AWOL:
I wasn't aware of that.
I thought it was pin zero and pin one.

I think that's what they meant

@AWOL:
Sho' you right! I'll edit.

outsider:
@AWOL:
Sho' you right! I'll edit.

outsider:
Pin 8 is PORTB,0, so :

PORTD = B11110111;

DDRD  = B11110111;



And:


PORTB = B00000001;
DDRB = B00000001;



But you *are* aware that pins 1 and Pin 8 is PORTB,0, so :
PORTD = B11110111;
DDRD = B11110111;


PORTB = B00000001;
DDRB = B00000001;



But you *are* aware that pins 0 and 1 are the serial RX and TX pins? are the serial RX and TX pins?

Would I have to edit any of the other code due to this? It references port d at some point, and i was wondering if I would have to reference port B as well?

But you're going to have a lot of bit shifting footwork with your variable split across 2 PORTs.

You'll have to watch out if you're using pins 9 to 13 that they're not inadvertently changed, be careful with direct port manipulation.

outsider:

digitalWrite(8,HIGH);

PinMode(8,OUTPUT);

"Unresolved reference to PinMode"

Thank you guys for all the suggestions!! I just ended up utilizing the port B solution, and I used an analog filter to fix the rest of the issue. Thank you all so much!!