Hi guys. I have a 9V - 1500mA output adapter. But the Arduino Uno R3 requires 7-12 V - 50mA supply.
Now how do I reduce current by 1450mA in just a range of two volts. Please give me a solution to this problem!
Look up Ohm's Law.
What is the input supply current and voltage to the jack then
I said look up Ohm's Law because it will tell you that the current draw is not decided or controlled by the arduino. It is simply a function of the resistance.
Now how do I reduce current by 1450mA in just a range of two volts. Please give me a solution to this problem!
As stated, the question is absurd. ( I want to say "stupid" but it is possible you simply don't know how to express what you are really trying to say)
Since asking us how to do something does not seem to be working, why don't you tell us WHY you want to do it first ?
The voltage at the jack is what you supply - 9v
The current will be whatever the micro needs - a minimum of 50ma
Your job is to make the minimum current available which, by supplying 1500mA, you are doing, with quite a bit to spare. The excess is irrelevant.
If you are going to develop Arduino projects it would be a good idea to learn the basic theory of electricity - Ohms law is a good place to start. Understanding the difference between volts, amps and watts is also important. If you are thinking of using batteries the difference between amps and amp-hrs is another thing to learn.
...R