interrup hangs up although function works in plain new sketch

Projects Programming
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2.62.ino (21.7 KB)

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Interrupt service routines are intended to be as short as possible. Yours looks rather complex. Interrupts are suspended while processing your routine, which is a problem because you're trying to use millis for timing and it's driven by, you guessed it, an interrupt.

You need to rethink your use of interrupts.

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Hello

wildbill:
....wich is a problem because you're trying to use millis for timing and it's driven by, you guessed it, an interrupt.

millis(); can be called in an ISR without problem , BUT millis() is stopped.

Regards,
bidouilleelec

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To clarify what you said, bidouilleelec, you can call millis() to get a snapshot of when the ISR was called but you can't use it for timing loops etc. within the routine, correct?

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Scottawildcat:
To clarify what you said, bidouilleelec, you can call millis() to get a snapshot of when the ISR was called but you can't use it for timing loops etc. within the routine, correct?

exactly

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Scottawildcat:
you can call millis() to get a snapshot of when the ISR was called but you can't use it for timing loops etc. within the routine, correct?

Which is not a problem as you would not have any timing loops etc in an ISR.

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    if (stimmen = true)

I think you mean:

    if (stimmen == true)

Or, since 'stimmen' is a boolean:

    if (stimmen)

Check for '=' vs '==' in the rest of your code. It is a very common mistake.

Note: For the case of "if (boolVar == false)" it is shorter to say "if (!boolVar)".