IR library

Can someone send to me an infrared library for arduino 1.0.1,
I tried to download from this web site A Multi-Protocol Infrared Remote Library for the Arduino and changed the :

#include <WProgram.h>
to
#include <Arduino.h>
in IRRemoteInt.h.

but it is still doesn't working.
Thanks.

Try here

I did what wrote there

Try reading section 6:
"6. Getting help on the forum"

the library name suppose to be colored in orange.

and it means that the library file is not good.

the library name suppose to be colored in orange.

#######################################
# Syntax Coloring Map For IRremote
#######################################

#######################################
# Datatypes (KEYWORD1)
#######################################

decode_results KEYWORD1
IRrecv KEYWORD1
IRsend KEYWORD1

#######################################
# Methods and Functions (KEYWORD2)
#######################################

blink13 KEYWORD2
decode KEYWORD2
enableIRIn KEYWORD2
resume KEYWORD2
enableIROut KEYWORD2
sendNEC KEYWORD2
sendSony KEYWORD2
sendRaw KEYWORD2
sendRC5 KEYWORD2
sendRC6 KEYWORD2
#
#######################################
# Constants (LITERAL1)
#######################################

NEC LITERAL1
SONY LITERAL1
RC5 LITERAL1
RC6 LITERAL1
UNKNOWN LITERAL1
REPEAT LITERAL1

I don't see "IRremote" or "IRremoteInt" in there - do you have a different version of the keywords file?

no I downloaded it from here :A Multi-Protocol Infrared Remote Library for the Arduino

OK, I just downloaded that .zip, made the required change to the "IRremoteInt.h" header file, restarted the IDE and wrote a simple sketch.

#include <IRremote.h>
#include <IRremoteInt.h>

IRrecv backOfTheSofa(2); // dummy pin - no hardware

void setup ()
{}

void loop ()
{}

It all compiled (can't say if it worked, because I don't have hardware)

Thanks man it is working.

Hello, This might be a very dumb question, but what is "the required change to the IRremoteInt.h header file" ??
I can't get it to work either and I can't see how inons12 got it to work.

Thank you for any reply.