Arduino is either 5v or 3.3v. This means that something will need to be between it and the 12-30v device.
Links to data sheets for the sensors are needed.
Hi,
Welcome to the forum.
Please read the first post in any forum entitled how to use this forum.
http://forum.arduino.cc/index.php/topic,148850.0.html.
Have you googled the manufacturers name and part number?
The part manufacturers are pretty common names for control I/O devices, so you should not have any problems.
Thanks.. Tom.. 
You want to use sensors. What is the target, what do You want to achieve?
You can always power them up in order to heat Your cabin.
@Nick_Pyner i did power them up to test them if they work.. easy 
problem is i dont want to frie my arduino somehow
@CrossRoads done.. you have them all. i dont know how to create links sorry
@TomGeorge thanks. hopefully i didnt do something wrong -.- yes i find all data sheets problem is those are all 12+ volt sensors and i dont want to frie my arduino somehow
@Railroader target is i can read them on arduino so i can make some small machine for fun pneumatic thing.. (becouse why would i buy PLC :D)
thanks for replays
the biggest problem is those sensors are all 12+v and i tried some sensors and when they open they send 12v to data.. i dont want to destroy arduino like that
i tried some sensors and when they open they send 12v to data.. i dont want to destroy arduino like that
So you use a voltage divider circuit to cut down the 12V to 5V.
https://learn.sparkfun.com/tutorials/voltage-dividers
i dont know how to create links sorry
Use the link icon 12 icons in from the left hand side. Failing that please read this:-
How to use this forum
If I lower the voltage, the current goes up, but the wenglor sensor (at least the one I have) works with 200mA, won't this be an issue for the arduino as well if we use a voltage divider?
If I lower the voltage, the current goes up
No, ohms law says it dosn't.
but the wenglor sensor (at least the one I have) works with 200mA
Don't confuse the input current with the output signal.
won't this be an issue for the arduino as well if we use a voltage divider?
No.
Post a schematic of what you propose just to be on the safe side.
Hi,
The last device, the displacement sensor can be powered and operated of the controller supply level.
Because ALL the others have PNP switched open collector/drain you will need a potential divider.
In hindsight NPN open collector/drain outputs would have been a better choice.
Tom...
The first one has an "Open Drain" output. That means you can connect it directly to an INPUT_PULLUP pin and the pin will go LOW when the sensor is activated. That is also true for "Open Collector" outputs, sometimes called "NPN" outputs.
johnwasser:
The first one has an "Open Drain" output. That means you can connect it directly to an INPUT_PULLUP pin and the pin will go LOW when the sensor is activated. That is also true for "Open Collector" outputs, sometimes called "NPN" outputs.
The first one is Open-Drain in PNP type or more correctly P-CH config.
I had to look twice.. :o
Tom...
Datasheet_148504.pdf (219 KB)
