Hello people,
the day I get an Arduino Duo with LCD and HC-SR04.
(Servo is already there)
The items are intended for permanent installation.
I've thought of something:
The distance sensor measures a distance and controls the servo to fit.
On 'display also what should appear, but there is something serious;-)
Can I set a value as "zero"?
From there, the HC-SR04 should measure the radius but on the
I need information as a display scope.
So as an example, the sensor measures 40cm, which should be "zero".
The sensor measures 30cm so we've got 10cm radius.
Then should automatically be calculated by the formula: u = 2 x ? x r
2 x ? x 10cm = 62.83 cm Something like
The display should appear: circumference about 62.83 cm
What do you think is feasible? I have the code I viewed as an example:
#include
LiquidCrystal lcd(11, 10, 9, 4, 5, 6, 7);
int pingPin = 13;
int inPin = 12;
void setup() {
lcd.begin(16, 2);
lcd.print("testing...");
}
void loop()
{
// establish variables for duration of the ping,
// and the distance result in inches and centimeters:
long duration, inches, cm;
// The PING))) is triggered by a HIGH pulse of 2 or more microseconds.
// Give a short LOW pulse beforehand to ensure a clean HIGH pulse:
pinMode(pingPin, OUTPUT);
digitalWrite(pingPin, LOW);
delayMicroseconds(2);
digitalWrite(pingPin, HIGH);
delayMicroseconds(10);
digitalWrite(pingPin, LOW);
// The same pin is used to read the signal from the PING))): a HIGH
// pulse whose duration is the time (in microseconds) from the sending
// of the ping to the reception of its echo off of an object.
pinMode(inPin, INPUT);
duration = pulseIn(inPin, HIGH);
// convert the time into a distance
inches = microsecondsToInches(duration);
cm = microsecondsToCentimeters(duration);
lcd.clear();
lcd.setCursor(0, 0);
lcd.print(inches);
lcd.print("in, ");
lcd.print(cm);
lcd.print("cm");
delay(100);
}
long microsecondsToInches(long microseconds)
{
// According to Parallax's datasheet for the PING))), there are
// 73.746 microseconds per inch (i.e. sound travels at 1130 feet per
// second). This gives the distance travelled by the ping, outbound
// and return, so we divide by 2 to get the distance of the obstacle.
return microseconds / 74 / 2;
}
long microsecondsToCentimeters(long microseconds)
{
// The speed of sound is 340 m/s or 29 microseconds per centimeter.
// The ping travels out and back, so to find the distance of the
// object we take half of the distance travelled.
return microseconds / 29 / 2;
How would I integrate that now. For your tips, I am very grateful.
Thank You