Hi,
I have bought an LCD Shield the other day and it was shipped today. My most important choice of buying it was that it was using only a handfull of pins and not all of them - but now i had to face reality - by plugging the shield onto the arduino all pins are covered - is there a way of adding these 'ports' the arduino has to the lcd shield as well? the way i could still use it for my breadboard?
which shield are you using? I'm a little confused by your post. The sheild is physically covering a few free pins and you can't access them (i.e. put wires in them)?? If this is the case, jsut solder a few wires to the header connectors at the board and you are set to go!
Its been this http://cgi.ebay.de/ws/eBayISAPI.dll?ViewItem&ssPageName=STRK:MEWNX:IT&item=130271305572 shield. And from looking at its connections it doesnt seem to take every possible pin (no, really just a very few) - so it would be possible to attach just such a pinbar on it i guess?
Seems like you have this board: http://www.nuelectronics.com/estore/index.php?main_page=project_lcd
its a pretty decent shield, takes 6 digital pins, 1 analog pin and the ISCP port. That means you have 5 analog ports and 7 digital pins avaiable.
I don't know what a pin bar is so can't help you there. Do you have a picture of that or a link to one?
seems to be the very same.
A Pinbar.. umm, i mean those black thinges in which you plug cables or the shields.
The schematic looks like all the pins are available on the PCB so you should be able to solder pin header sockets (pinbar ?) to the PCB so you can access the unused Arduino pins