Hello to everyone,
im a newbie in programming.
Now the problem im having is the following.
I need to get a loop inside the if statement when pressing the button 3 times to run.
Now how do i get a loop inside an if statement, i found the while and do while methods but i am not able to get them running. One other problem is how do i escape the loop when i press the button again and the count changes to == 1 so i can switch between the count1 ,2 ,3 statements .
I hope someone can help me out because im realy stuck at the moment.
happy Greetings
Daniel
const byte LED = 13;
const byte Button = A0;
byte ButtonState;
byte lastState = LOW;
byte count = 0;
void setup() {
Serial.begin(9600);
pinMode(LED, OUTPUT);
pinMode(Button, INPUT);
}
void loop() {
ButtonState = digitalRead(Button);
if(ButtonState && ButtonState != lastState) // button latch, no debounce needed.
{
if(count < 3) // This will check to see if the count is within a range of 0 - 255, and anything over that, it will reset count back to 0. Of course, this will happen anyways because count is a BYTE, and not an int or any other type.
count += 1; // same as count = count + 5;
else
count = 0;
Serial.println(count);
}
lastState = ButtonState;
if(count == 1)
{
analogWrite(LED, 0);
}
else if(count == 2)
{
analogWrite(LED, 255);
}
else if(count ==3)
{
analogWrite(LED, 0);
delay(500);
analogWrite(LED, 255);
}
}
You're thinking too small. You already have the loop function running over and over again. Instead of thinking about trapping you program inside a loop, think about setting up the state so that it ends up going to the same place each time the loop function runs.
Have a look at state machines. I believe there are some examples either on the IDE itself or here on the site. But a google search of state machine should get you an infinite amount of inforamtion.
suvawa:
Hello to everyone,
im a newbie in programming.
Now the problem im having is the following.
I need to get a loop inside the if statement when pressing the button 3 times to run.
Now how do i get a loop inside an if statement, i found the while and do while methods but i am not able to get them running. One other problem is how do i escape the loop when i press the button again and the count changes to == 1 so i can switch between the count1 ,2 ,3 statements .
After looking at your code I can't make sense of your comments because it looks like the code should already do what you describe - do a different thing after each button press.
You can put any code you like after an IF statement.
Perhaps you only want the code to run once when (for example) count == 3. In that case you need another variable that records the fact that the code has run. That variable could then be reset when count changes to a different value.
Thanks a lot for your answers that gave me the hint what i was doing wrong.
Now i got it working, but a new problem popped up once the counter hit 3 and the LED starts blinking the counter aint responding to Button pushes.So i cant get the counter back to 1 or 2. Any ideas on where i made a mistake this time ?
many greetings
Daniel
const byte LED = 13;
const byte Button = 2;
byte ButtonState;
byte lastState = LOW;
byte count = 0;
void setup() {
Serial.begin(9600);
pinMode(LED, OUTPUT);
pinMode(Button, INPUT);
}
void loop() {
ButtonState = digitalRead(Button);
if(ButtonState && ButtonState != lastState) // button latch, no debounce needed.
{
if(count < 3) // This will check to see if the count is within a range of 0 - 255, and anything over that, it will reset count back to 0. Of course, this will happen anyways because count is a BYTE, and not an int or any other type.
count += 1; // same as count = count + 5;
else
count = 0;
Serial.println(count);
}
lastState = ButtonState;
if(count == 1)
{
analogWrite(LED, 0);
}
else if(count == 2)
{
analogWrite(LED, 255);
}
if(count ==3)
{
digitalWrite(LED, HIGH); // turn the LED on (HIGH is the voltage level)
delay(1000); // wait for a second
digitalWrite(LED, LOW); // turn the LED off by making the voltage LOW
delay(1000);
}
}
if(count ==3)
{
digitalWrite(LED, HIGH); // turn the LED on (HIGH is the voltage level)
delay(1000); // wait for a second
digitalWrite(LED, LOW); // turn the LED off by making the voltage LOW
delay(1000);
}
Well, you probably have to push the button for 2 seconds at least, since you are delaying here.
Look at the demo several things at a time to see how to manage time using millis() rather than delay(). The delay() function prevents the Arduino from doing anything else and is really only suitable for quick-and-dirty test code.
