Doing like this nothig change.. still delay on Out still active after releasing activation iput for some seconds.. maybe hw problem?
this the code I used:
int In22 = 22; // Define "In22" init value 22
int Out24 = 24;
int buttonState=0;
void setup()
{
pinMode(In22, INPUT); // Set pin22 as input
pinMode(Out24,OUTPUT);
}
void loop()
{
buttonState=digitalRead(In22);
if (buttonState==HIGH){
digitalWrite(Out24, HIGH);
}
else{
digitalWrite(Out24,LOW);
}
}
nightcrawler218:
Hello,
Welcome to the community.
Cant understand the question properly but I think you are trying to lit the PIN14 led when pin13 is high.
Here is a probable solution
Goto your arduino IDE > File > Example > 02. Digital > Button
Here is the code
/* Button Turns on and off a light emitting diode(LED) connected to digital pin 13, when pressing a pushbutton attached to pin 2.
The circuit:
-
LED attached from pin 13 to ground
-
pushbutton attached to pin 2 from +5V
-
10K resistor attached to pin 2 from ground
-
Note: on most Arduinos there is already an LED on the board
attached to pin 13.
created 2005
by DojoDave http://www.0j0.org
modified 30 Aug 2011
by Tom Igoe
This example code is in the public domain.
http://www.arduino.cc/en/Tutorial/Button
*/
// constants won't change. They're used here to
// set pin numbers:
const int buttonPin = 2; // the number of the pushbutton pin
const int ledPin = 13; // the number of the LED pin
// variables will change:
int buttonState = 0; // variable for reading the pushbutton status
void setup() {
// initialize the LED pin as an output:
pinMode(ledPin, OUTPUT);
// initialize the pushbutton pin as an input:
pinMode(buttonPin, INPUT);
}
void loop() {
// read the state of the pushbutton value:
buttonState = digitalRead(buttonPin);
// check if the pushbutton is pressed.
// if it is, the buttonState is HIGH:
if (buttonState == HIGH) {
// turn LED on:
digitalWrite(ledPin, HIGH);
}
else {
// turn LED off:
digitalWrite(ledPin, LOW);
}
}
Button is connected to pin2. Only when you press the button the pin13 LED will glow.
Cheers.