No, If you write 0x11, that is the same as 0b 0001 0001 so you would be setting bit 4 and bit 0.
bit: 7 6 5 4 3 2 1 = register at 0x1C
AFS_SEL = x x
so
AFS_SEL = 3 would be
bit: 7 6 5 4 3 2 1 = register at 0x1C
AFS_SEL = 1 1
which is 0b 0001 1000 = 0x18 (hex)