Multiple float in, out functions at once

DOHHHHHHH

My comment was right: "and next is not fading"
but you don't do that with !sines[i + 1].done() :confused: Spot the sneaky error? maybe I should have said "and next is done fading" 8)

Try: (left the debug in but I'll guess you know how to remove that :smiley:

#include <FadeLed.h>

//91 step sine table 0 = 0 degree, 90 = 90 degree
const flvar_t SineTable[91] PROGMEM = {
  0,   4,   9,  13,  18,  22,  27,  31,  35,  40,
 44,  49,  53,  57,  62,  66,  70,  75,  79,  83,
 87,  91,  96, 100, 104, 108, 112, 116, 120, 124,
127, 131, 135, 139, 143, 146, 150, 153, 157, 160,
164, 167, 171, 174, 177, 180, 183, 186, 190, 192,
195, 198, 201, 204, 206, 209, 211, 214, 216, 219,
221, 223, 225, 227, 229, 231, 233, 235, 236, 238,
240, 241, 243, 244, 245, 246, 247, 248, 249, 250,
251, 252, 253, 253, 254, 254, 254, 255, 255, 255,
255};

//Make FadeLed object with a sine lookup table of 91 (0 to 90 including)
FadeLed sines[3] = {{3, SineTable, 90}, {5, SineTable, 90}, {9, SineTable, 90}};
const byte NrSines = sizeof(sines)/sizeof(sines[0]);

void setup(){
  Serial.begin(115200);
  
  for(byte i = 0; i < NrSines; i++){
    sines[i].setTime(1000); //halve period, 0% to 90% or 90% to 0%
  }
  
  for(byte i = 0; i < NrSines; i++){
    sines[i].beginOn();
    delay(1000);
    sines[i].begin(0);
  }
 
  //start the first
  sines[0].on();
  
  Serial.println(NrSines);
  Serial.println();
  
  for(byte i =0; i < NrSines; i++){
    Serial.println(sines[i].get());
    Serial.println(sines[i].getCurrent());
    Serial.println(sines[i].done());
    Serial.println();
  }
}

void loop(){
  FadeLed::update();
 
  for(byte i = 0; i < NrSines; i++){
    //for all but last (who has no next)
    if(i < (NrSines - 1)){
      //if >50% (45 degree) and next is not fading and is off
      if((sines[i].getCurrent() >= 45) && sines[i + 1].done() && (sines[i + 1].get() == 0)){
        sines[i + 1].on();
      }
    }
   
    //if sin is 100% (90 degree), fade back down
    if(sines[i].done() && sines[i].get()){
      sines[i].off();
    }
  }
}