My temperature readout for a 3d printer. with alarm

I wanted to make a simple 4 sensor temp readout and alarm for my 3d printers stepper motors. (i just burned one up ) I am a beginner. For sure.... I took a sample temp readout code and modded it. Have not tested it. I'm wondering if anyone has any input on why this would not work and how to make this code better.... Thank you

/*
3d Printer Stepper Temps...... In *F on a 16x2 i2c LCD.
Standard Thermister setups. Use voltage dividers(10K). Pin 0,1,2,3 go to respective thermisters.


Displays 
X87.98F Z67.98F    (examples number)
Y67.34F E34.56F

    Added An Alarm..... Have Not Tested It.
    Pin 4 goes to neg side of active peizo
*/


#include <LiquidCrystal_I2C.h>

LiquidCrystal_I2C lcd(0x27,16,2);

float TooHigh = 100.00;   //temp of alarm     //arlarm stuff



int ThermistorPinX = 0;
int ThermistorPinY = 1;
int ThermistorPinZ = 2;
int ThermistorPinE = 3;

int Vox;
int Voy;
int Voz;
int Voe;

float c1 = 1.009249522e-03, c2 = 2.378405444e-04, c3 = 2.019202697e-07;


//XXX
float R1x = 10000;
float logR2x, R2x, Tx;

//YYY
float R1y = 10000;
float logR2y, R2y, Ty;

//ZZZ
float R1z = 10000;
float logR2z, R2z, Tz;

//EEE
float R1e = 10000;
float logR2e, R2e, Te;


void setup() {
Serial.begin(9600);
lcd.init(); //initialize the lcd
lcd.backlight(); //open the backlight


}

void loop() {
   
//  XXXXX
  Vox = analogRead(ThermistorPinX);
  R2x = R1x * (1023.0 / (float)Vox - 1.0);
  logR2x = log(R2x);
  Tx = (1.0 / (c1 + c2*logR2x + c3*logR2x*logR2x*logR2x));
  Tx = Tx - 273.15;
  Tx = (Tx * 9.0)/ 5.0 + 32.0; 
  lcd.setCursor(0,0);
  lcd.print("X");
  lcd.print(Tx);   
  lcd.print("F");
  if (Tx > TooHigh) {                   //arlarm stuff
    digitalWrite (4, HIGH);             //arlarm stuff
  }

  //  YYYY
  Voy = analogRead(ThermistorPinY);
  R2y = R1y * (1023.0 / (float)Voy - 1.0);
  logR2y = log(R2y);
  Ty = (1.0 / (c1 + c2*logR2y + c3*logR2y*logR2y*logR2y));
  Ty = Ty - 273.15;
  Ty = (Ty * 9.0)/ 5.0 + 32.0; 
  lcd.setCursor(0,1);
  lcd.print("Y");
  lcd.print(Ty);   
  lcd.print("F");
  if (Ty > TooHigh) {                   //arlarm stuff
    digitalWrite (4, HIGH);             //arlarm stuff
  }

  //  ZZZZ
  Voz = analogRead(ThermistorPinZ);
  R2z = R1z * (1023.0 / (float)Voz - 1.0);
  logR2z = log(R2z);
  Tz = (1.0 / (c1 + c2*logR2z + c3*logR2z*logR2z*logR2z));
  Tz = Tz - 273.15;
  Tz = (Tz * 9.0)/ 5.0 + 32.0; 
  lcd.setCursor(9,0);
  lcd.print("Z");
  lcd.print(Tz);   
  lcd.print("F");
  if (Tz > TooHigh) {                   //arlarm stuff
    digitalWrite (4, HIGH);             //arlarm stuff
  }

  //  EEEE
  Voe = analogRead(ThermistorPinE);
  R2e = R1e * (1023.0 / (float)Voe - 1.0);
  logR2e = log(R2e);
  Te = (1.0 / (c1 + c2*logR2e + c3*logR2e*logR2e*logR2e));
  Te = Te - 273.15;
  Te = (Te * 9.0)/ 5.0 + 32.0; 
  lcd.setCursor(9,1);
  lcd.print("E");
  lcd.print(Te);   
  lcd.print("F");
  if (Te > TooHigh) {                    //arlarm stuff
    digitalWrite (4, HIGH);              //arlarm stuff
  }

  delay(1500);     //Updates the LCD every 1.5s... 
  lcd.clear();
}

Seems you're using the wrong motor driver and/or settings for your steppers.
In general, steppers should get warm, bot not so hot that they burn.
Trying to fix the problem with a temp sensor seems silly.
Tell us more about your hardware.
Leo..

Ya. I def had the stEpper driver too high. .650v instead of .4. It was my extruder motor. Mistakes suck. But I figured why not have a backup. Also, if I add a wire to the alarm pin on the arduino, plug that into a pin on the ramps, change some code and have a temp sensor pause.... I was just tinkinering around learning code... so, good start would be this.....
How does the code look.?

jt41time:
Have not tested it. I'm wondering if anyone has any input on why this would not work and how to make this code better....

Test first. If it does not work then ask for advice.

The Arduino system has been designed to make testing very simple.

And I agree with @Wawa

...R
Stepper Motor Basics