Hello people as u can see this is my first post here ;D
i bought an arduino uno and some equipment with it (ran all the basics and proggraming)
i didnt find a 7-segment display though i had an old device that had one
so i removed it but i really dont know what to do with it
the 7-segment display is 5631bh(chinise data sheets so couldnt really understand)
it has a 3 pnp transistors(3 digits)
already have resistors
here is some pics
i already did some small projects like using an ir reciver to controll the arduino/timed led etc etc
Thanks alot people of ardiuno
and sorry if i posted this in the wrong forum
Edit:it has 3 pnp transistors so it is a cathode display?
You seem to have mislaid the all-important IC "U2" which is the correct way of operating it.
and no icu2 was attached either
Well, that's funny, because something has clearly been removed from the position marked "U2" and it is not entirely clear how judging from the appearance of the solder.
And you did say you removed it from "an old device" so the question is - how, and what did the rest of the device look like?
So, it worked for your friend, eh?
Well, he clearly traced out the circuit, which is what you need to do.
You said PNP transistors. You will find the emitters connect to the positive supply terminal which you can connect to your 5 V. The bases of the three transistors will each have a resistor to one of the "U2" terminations and there will be a resistor from each segment cathode of the LED also to U2. If you connect the 5 V up to the board, you can take two ground wires and probe them as a pair to one of the base resistor points on U2 and one of the cathode resistor points; one of the segments will light up. All connections are made to the "U2" pinout, you do not need to connect to anywhere else.
This will allow you to identify the connections to allow you to connect those points to your Arduino in the correct order. Your code will then pull one transistor line low at a time while it pulls the corresponding segments low.