Hello,
I would require some help in calculating how much would this stepper be able to handle while managing to operate smoothly.
Im using Hanpose 17HS3401S - T8*8 with an axle, holding torque = 28 N / cm, also lenght of the axle is 10cm, not sure if Im supposed to provide any other data to be able to calculate maximum weight it can hold.
A diagram with the dimensions marked on it would be useful.
And a link to the datasheet for your stepper motor.
Keep in mind that the holding torque of a stepper motor will be greater than the running torque. You need to design for the running torque. The better motor manufacturers have graphs that show how torque varies with speed and motor supply voltage.
Hi,
here is the link from the page I bought it with necessary info, diagrams, hope this helps
Please explain, using a diagram posted in line, what you mean by "hold weight". Include dimensions.
Hi,
By "holding weight" I mean, how much of the weight 1kg or 3kg or ... would this stepper motor be able to lift and how much of weight is it able to hold at the axle without it being powered up
If you are asking what the holding torque is without any power to the motor, unless the bearings are frozen, the answer is ZERO weight.
The motor can only hold any position if it is properly powered!!!
Paul
Hi,
thanks for the reply, what would be the way to calculate how much weight it can hold while powered?
homunculus1133:
Hi,thanks for the reply, what would be the way to calculate how much weight it can hold while powered?
In your first post, you give the length of the axle. Did you REALLY mean the length of the lever attached to the axle? If so, your quote of the torque value for the motor gives the torque value for holding as well. Probably slightly less than the maximum movement torque.
Actual values will need to be measured on site.
Paul
homunculus1133:
Hi,here is the link from the page I bought it with necessary info, diagrams, hope this helps
https://www.aliexpress.com/item/32958631997.html
That link is for a stepper motor with a lead-screw fitted directly to the motor shaft.
Are you asking what weight the motor could lift if the lead-screw is oriented vertically?
I don't think anyone reading this Thread up to this point had any notion that that is what you had in mind.
And assuming I have guessed correctly I don't think it would be possible to calculate the max weight that could be lifted. There will be a lot of friction between the lead screw and the nut. Just do some experiments.
You will also need to consider what bearing is carrying the load and whether it might be overloaded.
...R
I don't think anyone reading this Thread up to this point had any notion that that is what you had in mind.
Agreed. POST A DRAWING SHOWING HOW THE WEIGHT WILL BE LIFTED or HELD BY THE MOTOR.
Give me a lever and a place to stand and I will move the earth.
Archimedes
jremington:
Agreed. POST A DRAWING SHOWING HOW THE WEIGHT WILL BE LIFTED or HELD BY THE MOTOR.
And that means a drawing that you make yourself to illustrate the machine that YOU are trying to make.
Not sure if I understand the problem but...
Seems to me like you're just trying to figure out how much weight a motor carry on a lever arm of length x. Just so you know, the length of the axle has nothing to do with the length of the motor-that depends on the strength of the axle itself.
This is basic physics. When you have a motor with a torque of 28Ncm(notice that its not N/cm) and a 10cm long lever arm, then the force that the motor can apply to the end of the lever is ~2.8N because 28Ncm = xN * 10cm. After that you can convert the force to weight easily.
I understand that 28Ncm is your holding torque: as others have said, you likely have to calculate the force/weight of the motor using running torque, which depends on the motor and the current supply to it.
Note: The weight the motor can carry also depends on the angle of the lever arm relative to a perpendicular axis to the motor assuming that the lever arm isn't in parallel with the motor. This involves a little trigonometry: Nm = N * m * sin(theta). I encourage you to watch some lessons on this if you are interested.
Hope this helps!
seanboe:
Seems to me like you're just trying to figure out how much weight a motor carry on a lever arm of length x.
I don't think so. See Reply #8 and the link it contains.
...R
